内存中排序 <set><map>类似
使用sort属性,我们可以通过在取回结果集后在内存中进行排序,然后返回一个经过排序的结果集合
数据库结构:
create table teamSort (id varchar(32),teamname varchar(32)); create table studentSort (name varchar(32),team_id varchar(32)); insert into teamSort values("1","team1"); insert into studentSort values("a","1"); insert into studentSort values("b","1"); insert into studentSort values("c","1");
pojo: student部分采用set集合,无实体类
package Collection.Sort; import java.util.Set; public class Team { private String id; private String teamname; private Set students; public String getId() { return id; } public void setId(String id) { this.id = id; } public String getTeamname() { return teamname; } public void setTeamname(String teamname) { this.teamname = teamname; } public Set getStudents() { return students; } public void setStudents(Set students) { this.students = students; } }
Team.hbm.xml
<?xml version="1.0" encoding="utf-8"?> <!DOCTYPE hibernate-mapping PUBLIC "-//Hibernate/Hibernate Mapping DTD 3.0//EN" "http://hibernate.sourceforge.net/hibernate-mapping-3.0.dtd"> <!-- Mapping file autogenerated by MyEclipse - Hibernate Tools --> <hibernate-mapping> <class name="Collection.Sort.Team" table="teamSort" > <id name="id" unsaved-value="null"> <generator class="uuid.hex"></generator> </id> <property name="teamname" type="string" column="teamname"></property> <!-- 以element内容升序返回 --> <set name="students" table="studentSort" cascade="all" sort="natural"> <key column="team_id"></key> <element type="string" column="name"></element> </set> </class> </hibernate-mapping>
Hibernate.cfg.xml
<?xml version='1.0' encoding='UTF-8'?> <!DOCTYPE hibernate-configuration PUBLIC "-//Hibernate/Hibernate Configuration DTD 3.0//EN" "http://hibernate.sourceforge.net/hibernate-configuration-3.0.dtd"> <!-- Generated by MyEclipse Hibernate Tools. --> <hibernate-configuration> <session-factory> <property name="connection.username">root</property> <property name="connection.url"> jdbc:mysql://localhost:3306/schoolproject?characterEncoding=gb2312&useUnicode=true </property> <property name="dialect"> org.hibernate.dialect.MySQLDialect </property> <property name="myeclipse.connection.profile">mysql</property> <property name="connection.password">1234</property> <property name="connection.driver_class"> com.mysql.jdbc.Driver </property> <property name="hibernate.dialect"> org.hibernate.dialect.MySQLDialect </property> <property name="hibernate.show_sql">true</property> <property name="current_session_context_class">thread</property> <property name="jdbc.batch_size">15</property> <mapping resource="Collection/Sort/Team.hbm.xml" /> </session-factory> </hibernate-configuration>
测试代码:
package Collection.Sort; import java.io.File; import java.util.Iterator; import java.util.Set; import org.hibernate.Session; import org.hibernate.SessionFactory; import org.hibernate.Transaction; import org.hibernate.cfg.Configuration; public class Test { public static void main(String[] args) { String filePath=System.getProperty("user.dir")+File.separator+"src/Collection/Sort"+File.separator+"hibernate.cfg.xml"; File file=new File(filePath); System.out.println(filePath); SessionFactory sessionFactory=new Configuration().configure(file).buildSessionFactory(); Session session=sessionFactory.openSession(); Transaction t=session.beginTransaction(); Team team=(Team)session.createQuery("from Team t where t.teamname='team1'").uniqueResult(); Set result=team.getStudents(); Iterator iter=result.iterator(); while(iter.hasNext()){ System.out.println(iter.next()); } t.commit(); } }
运行结果:
Hibernate: select team0_.id as id0_, team0_.teamname as teamname0_ from teamSort team0_ where team0_.teamname='team1'
Hibernate: select students0_.team_id as team1_0_, students0_.name as name0_ from studentSort students0_ where students0_.team_id=?
a
b
c
sort="natural"默认进行升序排列,如果我们想改成降序,则需要写一个类实现Comparator接口如下:
package Collection.Sort; import java.util.Comparator; public class Compare implements Comparator { public int compare(Object o1, Object o2) { String s1=(String)o1; String s2=(String)o2; if(s1.equals(s2)){ return 0; } else if(s1.compareTo(s2)>0){ return -1; } else{ return 1; } } }
然后更改Team.hbm.xml 配置sort属性
sort="Collection.Sort.Compare"
重新执行测试代码,结果如下:
Hibernate: select team0_.id as id0_, team0_.teamname as teamname0_ from teamSort team0_ where team0_.teamname='team1'
Hibernate: select students0_.team_id as team1_0_, students0_.name as name0_ from studentSort students0_ where students0_.team_id=?
c
b
a