python多线程ctrl-c退出问题

场景:

 

经常会遇到下述问题:很多io busy的应用采取多线程的方式来解决,但这时候会发现python命令行不响应ctrl-c 了,而对应的java代码则没有问题:

 

public class Test {
    public static void main(String[] args) throws Exception {

        new Thread(new Runnable() {

            public void run() {
                long start = System.currentTimeMillis();
                while (true) {
                    try {
                        Thread.sleep(1000);
                    } catch (Exception e) {
                    }
                    System.out.println(System.currentTimeMillis());
                    if (System.currentTimeMillis() - start > 1000 * 100) break;
                }
            }
        }).start();

    }
}

java Test

ctrl-c则会结束程序


而对应的python代码:

 

# -*- coding: utf-8 -*-
import time
import threading
start=time.time()
def foreverLoop():
    start=time.time()
    while 1:
        time.sleep(1)
        print time.time()
        if time.time()-start>100:
            break
            

thread_=threading.Thread(target=foreverLoop)
#thread_.setDaemon(True)
thread_.start()
 

python p.py


后ctrl-c则完全不起作用了。

 

 

不成熟的分析:

 

首先单单设置 daemon 为 true 肯定不行,就不解释了。当daemon为 false 时,导入python线程库后实际上,threading会在主线程执行完毕后,检查是否有不是 daemon 的线程,有的化就wait,等待线程结束了,在主线程等待期间,所有发送到主线程的信号也会被阻测,可以在上述代码加入signal模块验证一下:

 

def sigint_handler(signum,frame):  
    print "main-thread exit"
    sys.exit()  
signal.signal(signal.SIGINT,sigint_handler)
 

在100秒内按下ctrl-c没有反应,只有当子线程结束后才会出现打印 "main-thread exit",可见 ctrl-c被阻测了


threading 中在主线程结束时进行的操作:

_shutdown = _MainThread()._exitfunc
def _exitfunc(self):
        self._Thread__stop()
        t = _pickSomeNonDaemonThread()
        if t:
            if __debug__:
                self._note("%s: waiting for other threads", self)
        while t:
            t.join()
            t = _pickSomeNonDaemonThread()
        if __debug__:
            self._note("%s: exiting", self)
        self._Thread__delete()

 

 对所有的非daemon线程进行join等待,其中join中可自行察看源码,又调用了wait,同上文分析 ,主线程等待到了一把锁上。

 

不成熟的解决:

 

只能把线程设成daemon才能让主线程不等待,能够接受ctrl-c信号,但是又不能让子线程立即结束,那么只能采用传统的轮询方法了,采用sleep间歇省点cpu吧:

 

# -*- coding: utf-8 -*-
import time,signal,traceback
import sys
import threading
start=time.time()
def foreverLoop():
    start=time.time()
    while 1:
        time.sleep(1)
        print time.time()
        if time.time()-start>5:
            break
            
thread_=threading.Thread(target=foreverLoop)
thread_.setDaemon(True)
thread_.start()

#主线程wait住了,不能接受信号了
#thread_.join()

def _exitCheckfunc():
    print "ok"
    try:
        while 1:
            alive=False
            if thread_.isAlive():
                alive=True
            if not alive:
                break
            time.sleep(1)  
    #为了使得统计时间能够运行,要捕捉  KeyboardInterrupt :ctrl-c      
    except KeyboardInterrupt, e:
        traceback.print_exc()
    print "consume time :",time.time()-start
        
threading._shutdown=_exitCheckfunc

   缺点:轮询总会浪费点cpu资源,以及battery.


有更好的解决方案敬请提出。

 

ps1: 进程监控解决方案

 

用另外一个进程来接受信号后杀掉执行任务进程,牛

# -*- coding: utf-8 -*-
import time,signal,traceback,os
import sys
import threading
start=time.time()
def foreverLoop():
    start=time.time()
    while 1:
        time.sleep(1)
        print time.time()
        if time.time()-start>5:
            break

class Watcher:
    """this class solves two problems with multithreaded
    programs in Python, (1) a signal might be delivered
    to any thread (which is just a malfeature) and (2) if
    the thread that gets the signal is waiting, the signal
    is ignored (which is a bug).

    The watcher is a concurrent process (not thread) that
    waits for a signal and the process that contains the
    threads.  See Appendix A of The Little Book of Semaphores.
    http://greenteapress.com/semaphores/

    I have only tested this on Linux.  I would expect it to
    work on the Macintosh and not work on Windows.
    """

    def __init__(self):
        """ Creates a child thread, which returns.  The parent
            thread waits for a KeyboardInterrupt and then kills
            the child thread.
        """
        self.child = os.fork()
        if self.child == 0:
            return
        else:
            self.watch()

    def watch(self):
        try:
            os.wait()
        except KeyboardInterrupt:
            # I put the capital B in KeyBoardInterrupt so I can
            # tell when the Watcher gets the SIGINT
            print 'KeyBoardInterrupt'
            self.kill()
        sys.exit()

    def kill(self):
        try:
            os.kill(self.child, signal.SIGKILL)
        except OSError: pass

Watcher()            
thread_=threading.Thread(target=foreverLoop)
thread_.start()

 注意 watch()一定要放在线程创建前,原因未知。。。。,否则立刻就结束

 

 

ps2:类似的轮询join timeout

 

和我的实现太相似,可惜是后来总结时才发现,浪费脑细胞

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