MySQL 计算两个日期或时间的间隔 解决方法

1，使用时间函数

计算两个日期之间的间隔，可以使用DATEDIFF()函数

SELECT DATEDIFF('2010-06-01','2010-01-01'),DATEDIFF('2010-01-01','2010-06-01')
151 -151

SELECT DATEDIFF('2010-06-01','2010-01-01'),DATEDIFF('2010-01-01','2010-06-01')
151	-151

注意：DATEDIFF函数也可以作用于date-and-time，但是它会忽略时间只显示天数

使用TIMEDIFF()函数计算出两个TIME类型之间的时间间隔

mysql> SELECT TIMEDIFF('12:12:12','11:11:11');
 +---------------------------------+
 | TIMEDIFF('12:12:12','11:11:11') |
 +---------------------------------+
| 01:01:01                        |
 +---------------------------------+
 1 row in set (0.00 sec)

mysql> SELECT TIMEDIFF('12:12:12','11:11:11');
+---------------------------------+
| TIMEDIFF('12:12:12','11:11:11') |
+---------------------------------+
| 01:01:01                        |
+---------------------------------+
1 row in set (0.00 sec)

这里我添加一个TIMESTAMPDIFF(UNIT,TIME1,TIME2)函数

mysql>  SET @D1 = '1999-09-09 12:11:11', @D2 = '2009-09-09 12:11:11';
 Query OK, 0 rows affected (0.00 sec)

 mysql>  SELECT TIMESTAMPDIFF(MINUTE,@D1,@D2), TIMESTAMPDIFF(DAY,@D1,@D2);
 +-------------------------------+----------------------------+
 | TIMESTAMPDIFF(MINUTE,@D1,@D2) | TIMESTAMPDIFF(DAY,@D1,@D2) |
 +-------------------------------+----------------------------+
| 5260320                       | 3653                       |
 +-------------------------------+----------------------------+
 1 row in set (0.00 sec)

mysql>  SET @D1 = '1999-09-09 12:11:11', @D2 = '2009-09-09 12:11:11';
Query OK, 0 rows affected (0.00 sec)

mysql>  SELECT TIMESTAMPDIFF(MINUTE,@D1,@D2), TIMESTAMPDIFF(DAY,@D1,@D2);
+-------------------------------+----------------------------+
| TIMESTAMPDIFF(MINUTE,@D1,@D2) | TIMESTAMPDIFF(DAY,@D1,@D2) |
+-------------------------------+----------------------------+
| 5260320                       | 3653                       |
+-------------------------------+----------------------------+
1 row in set (0.00 sec)

2，把要处理的时间转换为基本时间单位，天或者是秒，然后再计算时间间隔

TIME_TO_SEC()

SELECT t1,t2,TIME_TO_SEC(t2) - TIME_TO_SEC(t1),TIME_TO_SEC(t1) - TIME_TO_SEC(t2) FROM time_val
05:01:30    02:30:20    -9070   9070
15:00:00    15:00:00     0  0
12:30:20    17:30:45    18025   -18025

SELECT t1,t2,TIME_TO_SEC(t2) - TIME_TO_SEC(t1),TIME_TO_SEC(t1) - TIME_TO_SEC(t2) FROM time_val
05:01:30	02:30:20	-9070	9070
15:00:00	15:00:00	 0	0
12:30:20	17:30:45	18025	-18025

TO_DAYS()

查看代码 复制到剪贴板

SELECT TO_DAYS('1999-09-09') - TO_DAYS('2009-09-09')
-3653

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