通过http/https的POST方式，发送、处理和接收XML文件内容

1.send:

C# code

  

   
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   WebRequest myHttpWebRequest 
   =
    WebRequest.Create(
   "
   http://abc.com/xxx.aspx
   "
   );

   //
    Set the 'Method' property of the 'Webrequest' to 'POST'.
   

   myHttpWebRequest.Method 
   =
    
   "
   POST
   "
   ;


   //
    Create a new string object to POST data to the Url.
   

   string
    postData 
   =
    
   @"
   <?xml version=
   "
   1.0
   "
    encoding=
   "
   UTF
   -
   8
   "
    ?>
   

   <
   ROOT
   >
   

   <
   CONFIG
   >
   

   <
   TYPE
   >
   IN 
   </
   TYPE
   >
   

   <
   WORKTYPE
   >
   2
    
   </
   WORKTYPE
   >
   

   </
   CONFIG
   >
   

   <
   DATA
   >
   

   <
   POLICY
   >
   

   <
   UNITCODE
   >
   分公司代码 
   </
   UNITCODE
   >
   

   <
   APPLYNO
   >
   投保单号码 
   </
   APPLYNO
   >
   

   <
   APPLYENDORSENO
   >
   批单申请号码 
   </
   APPLYENDORSENO
   >
   

   </
   POLICY
   >
   

   </
   DATA
   >
   

   </
   ROOT
   >
    
   "
   ;
   

   
ASCIIEncoding encoding 
   =
    
   new
    ASCIIEncoding ();

   byte
   [] byte1 
   =
    encoding.GetBytes (postData);


   //
    Set the content type of the data being posted.
   

   myHttpWebRequest.ContentType 
   =
    
   "
   application/x-www-form-urlencoded
   "
   ;


   //
    Set the content length of the string being posted.
   

   myHttpWebRequest.ContentLength 
   =
    byte1.Length;

Stream newStream 
   =
    myHttpWebRequest.GetRequestStream ();

newStream.Write (byte1, 
   0
   , byte1.Length);

   //
    Close the Stream object.
   

   newStream.Close ();

HttpWebResponse response 
   =
    myHttpWebRequest.GetResponse();

  

2.receive:

C# code

  

   
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   StreamReader reader 
   =
    
   new
    StreamReader (Reqeust.InputStream);
String xml 
   =
    reader.ReadToEnd();