自定义过滤条件的集合
List<Integer> numbers = Lists.newArrayList(1, 2, 3, 6, 10, 34, 57, 89); Predicate<Integer> acceptEven = new Predicate<Integer>() { @Override public boolean apply(Integer number) { return (number % 2) == 0; } }; List<Integer> evenNumbers = Lists.newArrayList(Collections2.filter(numbers, acceptEven)); Integer found = Collections.binarySearch(evenNumbers, 57); assertThat(found, lessThan(0));
从集合中剔除掉空值
List<String> withNulls = Lists.newArrayList("a", "bc", null, "def"); Iterable<String> withoutNuls = Iterables.filter(withNulls, Predicates.notNull()); assertTrue(Iterables.all(withoutNuls, Predicates.notNull()));
从集合中检查某一个条件
List<Integer> evenNumbers = Lists.newArrayList(2, 6, 8, 10, 34, 90); Predicate<Integer> acceptEven = new Predicate<Integer>() { @Override public boolean apply(Integer number) { return (number % 2) == 0; } }; assertTrue(Iterables.all(evenNumbers, acceptEven));
集合的反向过滤
List<Integer> evenNumbers = Lists.newArrayList(2, 6, 8, 10, 34, 90); Predicate<Integer> acceptOdd = new Predicate<Integer>() { @Override public boolean apply(Integer number) { return (number % 2) != 0; } }; assertTrue(Iterables.all(evenNumbers, Predicates.not(acceptOdd)));
集合元素类型转换
List<Integer> numbers = Lists.newArrayList(1, 2, 3); List<String> asStrings = Lists.transform(numbers, Functions.toStringFunction()); assertThat(asStrings, contains("1", "2", "3"));
集合的排序
List<Integer> numbers = Arrays.asList(2, 1, 11, 100, 8, 14); Ordering<Object> ordering = Ordering.natural().onResultOf(Functions.toStringFunction()); List<Integer> inAlphabeticalOrder = ordering.sortedCopy(numbers); List<Integer> correctAlphabeticalOrder = Lists.newArrayList(1, 100, 11, 14, 2, 8); assertThat(correctAlphabeticalOrder, equalTo(inAlphabeticalOrder));
集合的过滤与功能化
List<Integer> numbers = Arrays.asList(2, 1, 11, 100, 8, 14); Predicate<Integer> acceptEvenNumber = new Predicate<Integer>() { @Override public boolean apply(Integer number) { return (number % 2) == 0; } }; Function<Integer, Integer> powerOfTwo = new Function<Integer, Integer>() { @Override public Integer apply(Integer input) { return (int) Math.pow(input, 2); } }; FluentIterable<Integer> powerOfTwoOnlyForEvenNumbers = FluentIterable.from(numbers).filter(acceptEvenNumber).transform(powerOfTwo); assertThat(powerOfTwoOnlyForEvenNumbers, contains(4, 10000, 64, 196));
集合功能块的结合
List<Integer> numbers = Arrays.asList(2, 3); Function<Integer, Integer> powerOfTwo = new Function<Integer, Integer>() { @Override public Integer apply(Integer input) { return (int) Math.pow(input, 2); } }; List<Integer> result = Lists.transform(numbers, Functions.compose(powerOfTwo, powerOfTwo)); assertThat(result, contains(16, 81));
集合通过过滤器创建功能块
List<Integer> numbers = Lists.newArrayList(1, 2, 3, 6); Predicate<Integer> acceptEvenNumber = new Predicate<Integer>() { @Override public boolean apply(Integer number) { return (number % 2) == 0; } }; Function<Integer, Boolean> isEventNumberFunction = Functions.forPredicate(acceptEvenNumber); List<Boolean> areNumbersEven = Lists.transform(numbers, isEventNumberFunction); assertThat(areNumbersEven, contains(false, true, false, true));