226.

Maximum Depth of Binary Tree 226. Invert Binary Tree

258.AddDigitsDigitroot数根问题/***@param{number}num*@return{number}*/varaddDigits=function(num){varb=(num-1)%9+1;returnb;};//之所以num要-1再+1;是因为特殊情况下：当num是9的倍数时，0+9的数字根和0的数字根不同。性质说明1.任何数加9的数字根还是它本身。（特殊情况num=
天才老王1993·2016-07-29 17:00

Leetcode 226. Invert Binary Tree (Easy) (cpp)

Leetcode226.InvertBinaryTree(Easy)(cpp)Tag:TreeDifficulty:Easy/* 226.InvertBinaryTree(Easy) Invertabinarytree. 4 /\ 27 /\/\ 1369 to 4 /\ 72 /\/\ 9631 */ /** *Definitionforabinarytreenode. *structT
Niko_Ke·2016-07-24 17:00

Easy-题目4：226. Invert Binary Tree

题目原文：Invertabinarytree.4 /\27/\/\1369to4/\72/\/\9631Trivia:ThisproblemwasinspiredbythisoriginaltweetbyMaxHowell:Google:90%ofourengineersusethesoftwareyouwrote(Homebrew),butyoucan’tinvertabinarytreeona
cmershen·2016-05-30 19:00

[置顶] 【LeetCode】226. Invert Binary Tree 解题报告

转载请注明出处：http://blog.csdn.net/crazy1235/article/details/51527554Subject出处：https://leetcode.com/problems/invert-binary-tree/Invertabinarytree.4 /\27 /\/\1369to4 /\72 /\/\9631Explain该题目相当简单，就是一个简单的二叉树左右对
crazy1235·2016-05-29 00:00

226. Invert Binary Tree [easy] (Python)

题目链接https://leetcode.com/problems/invert-binary-tree/题目原文Invertabinarytree.4/\27/\/\1369to4/\72/\/\9631Trivia:ThisproblemwasinspiredbythisoriginaltweetbyMaxHowell:Google:90%ofourengineersusethesoftwar
coder_orz·2016-05-12 14:34

226. Invert Binary Tree [easy] (Python)

题目链接https://leetcode.com/problems/invert-binary-tree/题目原文Invertabinarytree.4 /\27 /\/\1369to4 /\72 /\/\9631Trivia:ThisproblemwasinspiredbythisoriginaltweetbyMaxHowell:Google:90%ofourengineersusethesof
coder_orz·2016-05-12 14:00

leetcode 226. Invert Binary Tree

Invertabinarytree.4 /\ 27 /\/\ 1369to4 /\ 72 /\/\ 9631classSolution{ public: TreeNode*invertTree(TreeNode*root){ if(root==NULL) returnNULL; vectorque; que.push_back(root); while(!que.empty()) { vecto
u014568921·2016-05-04 13:00

LeetCode 226. Invert Binary Tree

递归的思想/***Definitionforabinarytreenode.*structTreeNode{*intval;*structTreeNode*left;*structTreeNode*right;*};*/ structTreeNode*invertTree(structTreeNode*root){ if(root==NULL) returnNULL; else { struct
qq_34788352·2016-05-03 20:00

226. Invert Binary Tree

Invertabinarytree.4 /\27 /\/\1369to4 /\72 /\/\9631Trivia:ThisproblemwasinspiredbythisoriginaltweetbyMaxHowell:Google:90%ofourengineersusethesoftwareyouwrote(Homebrew),butyoucan’tinvertabinarytreeonawh
zhangjian5021275·2016-05-02 15:00

【LeetCode】226. Invert Binary Tree 二叉树翻转

题目：理解：将二叉树的左右子树进行交换。代码：/** *Definitionforabinarytreenode. *structTreeNode{ *intval; *TreeNode*left; *TreeNode*right; *TreeNode(intx):val(x),left(NULL),right(NULL){} *}; */ classSolution{ public: TreeN
tmylzq187·2016-04-18 13:00

226.[LeetCode]Invert Binary Tree

题意：反转一个二叉树递归：classSolution{ public: TreeNode*invertTree(TreeNode*root){ //如果是NULL，则返回本身 if(root==NULL)returnroot; //如果左右其中有一个是非空的，则交换左右 if(root->left!=NULL||root->right!=NULL){ root->left=invertTree(r
qq_28057541·2016-04-17 01:00

leetcode 226. Invert Binary Tree 题解

226.InvertBinaryTree提交网址： https://leetcode.com/problems/invert-binary-tree/TotalAccepted:84040TotalSubmissions:186266Difficulty:Easy ACrate:45.1%Invertabinarytree.   4  / \ 2  7 /\ /\1 36 9   to   4  
yanglr2010·2016-04-13 23:00

LeetCode 226. Invert Binary Tree

Invertabinarytree.4 /\ 27 /\/\ 1369to4 /\ 72 /\/\ 9631Thisistoapplyrecursion.TreeNode*invertTree(TreeNode*root){ if(!root)returnNULL;//endcase. TreeNode*left=invertTree(root->left);//inverttheleft; Tr
github_34333284·2016-04-13 06:00

DRM初始化过程

drm_core_init这个函数是通过module（drm_core_init）明确在系统启动时进行调用.指定设备的major号，linux中默认为226.创建并初始化一个idr机制，这个机制其实原理上就是一个哈希表
jacob_wjj·2016-04-05 15:28

226. Invert Binary Tree | Java最短代码实现

原题链接：226.InvertBinaryTree【思路】对于每个节点，交换左右子树，然后递归左右子树，这样就实现了数的反转：publicTreeNodeinvertTree(TreeNoderoot){ if(root==null)returnroot; TreeNodetmp=root.left; root.left=root.right; root.right=tmp; invertTree
happyaaaaaaaaaaa·2016-03-27 00:00

LeetCode笔记：226. Invert Binary Tree

问题：Invertabinarytree.toTrivia:Google:90%ofourengineersusethesoftwareyouwrote(Homebrew),>butyoucan’tinvertabinarytreeonawhiteboardsofuckoff.大意：反转一个二叉树。从到琐事：Google表示如果你连反转二叉树都做不到就滚吧。思路：对于二叉树的每个子节点的左右节点都
Cloudox_·2016-03-26 15:00

LeetCode笔记：226. Invert Binary Tree

问题：Invertabinarytree.toTrivia:Google:90%ofourengineersusethesoftwareyouwrote(Homebrew),>butyoucan’tinvertabinarytreeonawhiteboardsofuckoff.大意：反转一个二叉树。从到琐事：Google表示如果你连反转二叉树都做不到就滚吧。思路：对于二叉树的每个子节点的左右节点都
Cloudox_·2016-03-26 15:00

[Leetcode]226. Invert Binary Tree My Submissions Question

Invertabinarytree.4/\27/\/\1369to4/\72/\/\9631很easy的问题，利用递归来进行树结点的转置publicclassSolution{ publicTreeNodeinvertTree(TreeNoderoot){ if(root==null)returnroot; TreeNodetmp=root.left; root.left=invertTree(r
·2016-03-25 13:00

leetcode 226. Invert Binary Tree

leetcode226.InvertBinaryTree题目TotalAccepted:76777TotalSubmissions:172853Difficulty:EasyInvertabinarytree.4/\27/\/\1369to4/\72/\/\9631答案/** *Definitionforabinarytreenode. *structTreeNode{ *intval; *Tre
Decorator2015·2016-03-15 16:00

226. Invert Binary Tree

nvertabinarytree.4 /\ 27 /\/\ 1369to4 /\ 72 /\/\ 9631Trivia:Thisproblemwasinspiredby thisoriginaltweet by MaxHowell:Google:90%ofourengineersusethesoftwareyouwrote(Homebrew),butyoucan’tinvertabinarytre
a342500329a·2016-03-09 16:00

LeetCode 226. Invert Binary Tree

1/** 2*Definitionforabinarytreenode. 3*structTreeNode{ 4*intval; 5*TreeNode*left; 6*TreeNode*right; 7*TreeNode(intx):val(x),left(NULL),right(NULL){} 8*}; 9*/ 10classSolution{ 11public: 12Tr
co0oder·2016-03-02 20:00

Leet Code OJ 226. Invert Binary Tree [Difficulty: Easy]

题目：Invertabinarytree.4/\27/\/\1369to4/\72/\/\9631思路分析：题意是将二叉树所有左右子数对调，如上图所示。具体做法是，先递归处理左右子树，然后将当前的左右子树对调。代码实现：/** *Definitionforabinarytreenode. *publicclassTreeNode{ *intval; *TreeNodeleft; *TreeNode
Lnho2015·2016-02-26 14:00

LeetCode 226. Invert Binary Tree

Invertabinarytree.4 /\ 27 /\/\ 1369to4 /\ 72 /\/\ 9631分析：又是二叉树的问题，很多二叉树的问题可以用递归算法来解决。先判断当前结点是否为空，此为递归的出口；接下来交换左孩子和右孩子的位置，分别以左孩子和右孩子为结点，继续递归循环判断是否有左孩子或者右孩子，进而继续交换位置。Java代码如下：/** *Definitionforabinarytr
Appletable·2016-02-12 20:00

leetCode 226. Invert Binary Tree

  题目链接：https://leetcode.com/problems/invert-binary-tree/  题目内容：Invertabinarytree.4 /\ 27 /\/\ 1369to4 /\ 72 /\/\ 9631  题目分析：  当然AC觉得这是道很简单的题，是自己想复杂了（人家本身就放在easy程度的=.=）。一开始我的想法除了考虑空指针这些问题（必须的啦~），还考虑了如果
shen_jz2012·2016-01-23 02:00

LeetCode - 226. Invert Binary Tree #Java

QuestionInvertabinarytree.翻转二叉树44/\/\27to72/\/\/\/\13699631这题的槽点是Thisproblemwasinspiredby[thisoriginaltweet](https://twitter.com/mxcl/status/608682016205344768)by[MaxHowell](https://twitter.com/mxcl)S
Sinexs·2016-01-15 11:50

【LeetCode】226. Invert Binary Tree

QuestionInvertabinarytree.4 /\27 /\/\1369to4 /\72 /\/\9631CodeBFS:/***Definitionforabinarytreenode.*structTreeNode{*intval;*TreeNode*left;*TreeNode*right;*TreeNode(intx):val(x),left(NULL),right(NULL){
jiange_zh·2016-01-07 20:00

226. Invert Binary Tree

226.InvertBinaryTreeTotalAccepted: 57653 TotalSubmissions: 136144 Difficulty: EasyInvertabinarytree.4 /\ 27 /\/\ 1369to4 /\ 72 /\/\ 9631Trivia:Thisproblemwasinspiredby thisoriginaltweet by MaxHowell:G
EbowTang·2015-12-28 20:00

226. Invert Binary Tree

226.InvertBinaryTreeMySubmissionsQuestionTotalAccepted: 57653 TotalSubmissions: 136144 Difficulty: EasyInvertabinarytree.4 /\ 27 /\/\ 1369to4 /\ 72 /\/\ 9631Trivia:Thisproblemwasinspiredby thisorigina
EbowTang·2015-12-28 20:00

[leetcode] 226. Invert Binary Tree 解题报告

题目链接：https://leetcode.com/problems/invert-binary-tree/Invertabinarytree.4 /\ 27 /\/\ 1369to4 /\ 72 /\/\ 9631Trivia:Thisproblemwasinspiredby thisoriginaltweet by MaxHowell:Google:90%ofourengineersuseth
qq508618087·2015-12-25 04:00

226. Invert Binary Tree

Invertabinarytree.4 /\ 27 /\/\ 1369to4 /\ 72 /\/\ 9631#Definitionforabinarytreenode. #classTreeNode(object): #def__init__(self,x): #self.val=x #self.left=None #self.right=None classSolution(object):
Mtchy·2015-12-23 11:00

【LeetCode】226. Invert Binary Tree

Invert Binary Tree Invert a binary tree. 4 / \ 2 7 / \ / \ 1 3 6 9 to 4 / \ 7 2 / \ / \ 9 6 3 1 Trivia:This problem was inspired by this
·2015-11-02 16:19

beetl 使用量稳步增长

这周beetl使用量是102个下载，freemaker国内下载量是226.
闲大赋·2015-09-16 10:00

判断素数

inta,b,c;221.boolprime;222.prime=true;223.cin>>a;224.c=int(sqrt(a));         225.for(b=2;b<=c;b++)     226
mengying1991·2012-11-18 15:00

Oracle学习 笔记

sqlplusw212. cmd（sqlplusscott/zgl）213. sqlplusdev21c) 登录数据库的常用的用户；214. sys/zgl（网络管理员）225. system/zgl（本地管理员）226
zgl707216·2012-10-21 00:00
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