ExpandoObject对象的JSON序列化
如果：
dynamic expando = new ExpandoObject();
d.SomeProp=SomeValueOrClass;
然后，我们在控制器中：
return new JsonResult(expando);
那么，我们的前台将会得到：
[{"Key":"SomeProp", "Value": SomeValueOrClass}]
而实际上，我们知道，JSON 格式的内容，应该是这样的：
{SomeProp: SomeValueOrClass}
于是乎，我们需要一个自定义的序列化器，它应该如下：
public class ExpandoJSONConverter : JavaScriptConverter
{
public override IEnumerable<Type> SupportedTypes
{
get
{
return new ReadOnlyCollection<Type>(new Type[] { typeof(System.Dynamic.ExpandoObject) });
}
}public override object Deserialize(IDictionary<string, object> dictionary, Type type, JavaScriptSerializer serializer)
{
throw new NotImplementedException();
}public override IDictionary<string, object> Serialize(object obj, JavaScriptSerializer serializer)
{
var result = new Dictionary<string, object>();
var dictionary = obj as IDictionary<string, object>;
foreach (var item in dictionary)
{
result.Add(item.Key, item.Value);
}return result;
}
}
现在，我们的控制器应该像这样写：
public ContentResult GetSomeThing(string categores)
{
return ControllProctector.Do1(() =>
{…
var serializer = new JavaScriptSerializer();
serializer.RegisterConverters(new JavaScriptConverter[] { new ExpandoJSONConverter() });
var json = serializer.Serialize(expando);
return new ContentResult
{
Content = json,
ContentType = "application/json"
};
});
}
我们的浏览器就能得到正确的 JSON 字符串了。
备注：其它的方法还有
一：
dynamic expando = new ExpandoObject();
expando.Blah = 42;
expando.Foo = "test";
...var d = expando as IDictionary<string, object>;
d.Add("SomeProp", SomeValueOrClass);// After you've added the properties you would like.
d = d.ToDictionary(x => x.Key, x => x.Value);
return new JsonResult(d);
二： JSON.NET
dynamic expando = new ExpandoObject();
expando.name = "John Smith";
expando.age = 30;var json = JsonConvert.SerializeObject(expando);
三：Content-method:
public ActionResult Data()
{
dynamic expando = new ExpandoObject();
expando.name = "John Smith";
expando.age = 30;var json = JsonConvert.SerializeObject(expando);
return Content(json, "application/json");
}