Python 日期处理

## 格式化时间输出

d1 = datetime.datetime(2016,11,12)
d2 = datetime.datetime(2016,1,12)
print d1.strftime("%d/%b/%y")	# 12/Nov/16
print d2.strftime("%Y-%m-%d")	# 2016-01-12

## 计算两个日期之间差多少天

print d2-d1						# -305 days, 0:00:00
datetime.datetime.now()+datetime.timedelta(days=-10)	# 2016-04-29 14:28:28.771000

python datetime与字符串互转

  (2012-08-29 19:44:05)

转载▼

datetime转成字符串：

date=datetime.datetime.now()

str=date.strftime("%Y-%m-%d %H:%M:%S")

print(date)

print(str)

输出：

2012-08-29 19:45:57.997000

2012-08-29 19:45:57

字符串转成datetime:

    str = '2012-08-29 19:45:57'

    date = time.strptime(str, "%Y-%m-%d %H:%M:%S")

    print(date)

输出

time.struct_time(tm_year=2012, tm_mon=8, tm_mday=29, tm_hour=19, tm_min=45, tm_sec=57, tm_wday=2, tm_yday=242, tm_isdst=-1)

Ref: python中关于时间和日期函数的常用计算总结(time和datatime)_python_脚本之家 http://www.jb51.net/article/34621.htm