Python实现使用turtle绘制圣诞树

简单的绘制圣诞树

新建tree1.py或者直接输入下面代码运行

#声明树的高度
height = 5
#树的雪花数，初始为1
stars = 1
#以数的高度作为循环次数

for i in range(height):
    print((' ' * (height - i)) + ('*' * stars))
    stars += 2
#输出树干
print((' ' * height) + '|')

使用turtle绘制简单圣诞树

新建tree2py，输入以下代码

#导入turtle库
import turtle
#设置屏幕大小
screen = turtle.Screen()
screen.setup(800,600)
#获取画笔并设置一些属性：圆形、红色、快
circle = turtle.Turtle()
circle.shape('circle')
circle.color('red')
circle.speed('fastest')
#抬起画笔
circle.up()
#重新获取画笔
square = turtle.Turtle()
#重新设置画笔属性：四方形、绿色、快
square.shape('square')
square.color('green')
square.speed('fastest')
#重新抬起画笔
square.up()
#跳到指定坐标位置
circle.goto(0,280)
#复制当前图形
circle.stamp()
k = 0
for i in range(1, 17):
    y = 30*i
    for j in range(i-k):
        x = 30*j
        square.goto(x,-y+280)
        square.stamp()
        square.goto(-x,-y+280)
        square.stamp()
    if i % 4 == 0:
        x = 30*(j+1)
        circle.color('red')
        circle.goto(-x,-y+280)
        circle.stamp()
        circle.goto(x,-y+280)
        circle.stamp()
        k += 2
    if i % 4 == 3:
        x = 30*(j+1)
        circle.color('yellow')
        circle.goto(-x,-y+280)
        circle.stamp()
        circle.goto(x,-y+280)
        circle.stamp()
square.color('brown')
for i in range(17,20):
    y = 30*i
    for j in range(3):
        x = 30*j
        square.goto(x,-y+280)
        square.stamp()
        square.goto(-x,-y+280)
        square.stamp()
turtle.exitonclick()

运行：

使用Turtle绘制复杂圣诞树

新建tree3.py，输入以下代码

#导入所依赖的库
from turtle import *
import random
import time
 
n = 80.0
#设置速度快
speed("fastest")
#背景颜色 海贝壳色，偏粉色
screensize(bg='seashell')
left(90)
forward(3*n)
color("orange", "yellow")
begin_fill()
left(126)

for i in range(5):
    forward(n/5)
    right(144)
    forward(n/5)
    left(72)
end_fill()
right(126)

color("dark green")
backward(n*4.8)
def tree(d, s):
    if d <= 0: return
    forward(s)
    tree(d-1, s*.8)
    right(120)
    tree(d-3, s*.5)
    right(120)
    tree(d-3, s*.5)
    right(120)
    backward(s)
tree(15, n)
backward(n/2)

for i in range(200):
    a = 200 - 400 * random.random()
    b = 10 - 20 * random.random()
    up()
    forward(b)
    left(90)
    forward(a)
    down()
    if random.randint(0, 1) == 0:
            color('tomato')
    else:
        color('wheat')
    circle(2)
    up()
    backward(a)
    right(90)
    backward(b)
time.sleep(60)

运行：

源码下载

https://download.csdn.net/download/badao_liumang_qizhi/10874465