iOS 自定义弹出视图 几行代码可以自定义任何弹出视图

首先，设置一个视图弹出的触发事件，我用的是一个button点击事件

UIButton * button3 = [UIButton buttonWithType:UIButtonTypeCustom];

    button3.frame = CGRectMake(22, 342, self.view.frame.size.width-44, 36);

     [button3 setTitle:@"00:00" forState:UIControlStateNormal];

    [button3 setTitleColor:[UIColor redColor] forState:UIControlStateNormal];

    [button3 addTarget:self action:@selector(showView) forControlEvents:UIControlEventTouchUpInside];

    [self.view addSubview:button3];

然后写button的点击触发事件

-(void)showView{

//设置弹出视图

    UIView * view = [[UIView alloc]initWithFrame:CGRectMake(22, 400, 120, 222)];

    view.backgroundColor = [UIColor redColor];

//实现弹出方法

       UIWindow *window = [[UIApplication sharedApplication].windows lastObject];

    window.windowLevel = UIWindowLevelNormal;

      [keywindow addSubview:view];

}

最后简单说一下，当你有了view以后可以随意定义任何控件了