1060 Are They Equal (25)

If a machine can save only 3 significant digits, the float numbers 12300 and 12358.9 are considered equal since they are both saved as 0.123*10^5^ with simple chopping. Now given the number of significant digits on a machine and two float numbers, you are supposed to tell if they are treated equal in that machine.

Input Specification:

Each input file contains one test case which gives three numbers N, A and B, where N (<100) is the number of significant digits, and A and B are the two float numbers to be compared. Each float number is non-negative, no greater than 10^100^, and that its total digit number is less than 100.

Output Specification:

For each test case, print in a line "YES" if the two numbers are treated equal, and then the number in the standard form "0.d~1~...d~N~*10\^k" (d~1~>0 unless the number is 0); or "NO" if they are not treated equal, and then the two numbers in their standard form. All the terms must be separated by a space, with no extra space at the end of a line.

Note: Simple chopping is assumed without rounding.

Sample Input 1:

3 12300 12358.9

Sample Output 1:

YES 0.123*10^5

Sample Input 2:

3 120 128

Sample Output 2:

NO 0.120*10^3 0.128*10^3

#include
#include
#include
#include
using namespace std;
int n;
string deal(string s, int& e){
	int k=0;
	while(s.length()>0 && s[0]=='0'){				//去除前导0 
		s.erase(s.begin());
	}
	if(s[0]=='.'){									//去除后如果第一位是小数点 
		s.erase(s.begin());
		while(s.length() > 0 && s[0]=='0'){			//去除小数点后判断有几个0，每有一个则指数-1 
			s.erase(s.begin());
			e--;
		}
	} else{											//如果第一位不是0那么判断小数点前有几位数字 
		while(k>n>>s1>>s2;
	int e1=0, e2=0;
	s3=deal(s1, e1);
	s4=deal(s2, e2);
	if(s3==s4 && e1==e2){
		cout<<"YES 0."<