杭电oj 1006 Tick and Tick

Tick and Tick

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 18985    Accepted Submission(s): 4871


Problem Description
The three hands of the clock are rotating every second and meeting each other many times everyday. Finally, they get bored of this and each of them would like to stay away from the other two. A hand is happy if it is at least D degrees from any of the rest. You are to calculate how much time in a day that all the hands are happy.
 

Input
The input contains many test cases. Each of them has a single line with a real number D between 0 and 120, inclusively. The input is terminated with a D of -1.
 

Output
For each D, print in a single line the percentage of time in a day that all of the hands are happy, accurate up to 3 decimal places.
 

Sample Input
 
   
0 120 90 -1
 

Sample Output
 
   
100.000 0.000 6.251
 

Author
PAN, Minghao
 

Source
ZJCPC2004
 


#include
#include
#include
//#define LOCAL
using namespace std;
double max(double a,double b,double c)
{
    return a>b?(a>c?a:c):(b>c?b:c);
}

double min(double a,double b,double c)
{
    return a>n)
    {
        if(n==-1)
            break;
        sum = 0;
        _nsm = n*sm;
        _nsh = n*sh;
        _nmh = n*mh;
        not_nsm = _360sm-_nsm;
        not_nsh = _360sh-_nsh;
        not_nmh = _360mh-_nmh;
        start_happy = max(_nsm,_nsh,_nmh);
        end_happy = min(not_nsm,not_nsh,not_nmh);
        while(start_happy<=43200&&end_happy<=43200)
        {
            start_happy = max(_nsm,_nsh,_nmh);
            end_happy = min(not_nsm,not_nsh,not_nmh);
            if(start_happy


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