POJ 1703 Find them, Catch them 并查集 （关系问题 判断是否在一个集合）

Description


The police office in Tadu City decides to say ends to the chaos, as launch actions to root up the TWO gangs in the city, Gang Dragon and Gang Snake. However, the police first needs to identify which gang a criminal belongs to. The present question is, given two criminals; do they belong to a same clan? You must give your judgment based on incomplete information. (Since the gangsters are always acting secretly.) 


Assume N (N <= 10^5) criminals are currently in Tadu City, numbered from 1 to N. And of course, at least one of them belongs to Gang Dragon, and the same for Gang Snake. You will be given M (M <= 10^5) messages in sequence, which are in the following two kinds: 


1. D [a] [b] 
where [a] and [b] are the numbers of two criminals, and they belong to different gangs. 


2. A [a] [b] 
where [a] and [b] are the numbers of two criminals. This requires you to decide whether a and b belong to a same gang. 
Input


The first line of the input contains a single integer T (1 <= T <= 20), the number of test cases. Then T cases follow. Each test case begins with a line with two integers N and M, followed by M lines each containing one message as described above.
Output


For each message "A [a] [b]" in each case, your program should give the judgment based on the information got before. The answers might be one of "In the same gang.", "In different gangs." and "Not sure yet."
Sample Input


1
5 5
A 1 2
D 1 2
A 1 2
D 2 4
A 1 4
Sample Output


Not sure yet.
In different gangs.

In the same gang.

题意: N个人,M次操作 若是A 则判断二者的关系,若是D 则确认二者不是同一阵营.
思路:并查集,之间的大多题目都是判断是否处于同一连通分量,这次则是判断是否处于同一集合,

所以还需要一个数组存储与根节点的关系

（此题目与POJ 1182食物链 类似）

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