Linux内核的块设备驱动有能力读取磁盘的序列号,这个数据存储在磁盘的控制芯片ROM里面。内核应该以怎样的形式将这个序列号呈现给调用者呢?我们ls一下这个目录:
/dev/disk/by-id
ll /dev/disk/by-id/static char *strip (char *s)
{
char *e;
while (*s == ' ') ++s;
if (*s)
for (e = s + strlen(s); *--e == ' '; *e = '\0');
return s;
}
static void dump_identity (__u16 *idw)
{
int i;
char pmodes[64] = {0,}, dmodes[128]={0,}, umodes[128]={0,};
char *model = strip(strndup((char *)&idw[27], 40));
char *fwrev = strip(strndup((char *)&idw[23], 8));
char *serno = strip(strndup((char *)&idw[10], 20));
__u8 tPIO;
printf("\n Model=%.40s, FwRev=%.8s, SerialNo=%.20s", model, fwrev, serno);
...
}
很明显,在显示序列号时,strip去掉了首尾的空格,因为空格显示出来是没有意义的。这十分正常。然而...
void ide_fixstring (u8 *s, const int bytecount, const int byteswap)
{
u8 *p = s, *end = &s[bytecount & ~1]; /* bytecount must be even */
if (byteswap) {
/* convert from big-endian to host byte order */
for (p = end ; p != s;) {
unsigned short *pp = (unsigned short *) (p -= 2);
*pp = ntohs(*pp);
}
}
/* strip leading blanks */
while (s != end && *s == ' ')
++s;
/* compress internal blanks and strip trailing blanks */
while (s != end && *s) {
if (*s++ != ' ' || (s != end && *s && *s != ' '))
*p++ = *(s-1);
}
/* wipe out trailing garbage */
while (p != end)
*p++ = '\0';
}
几乎是hdparm的strip更加严格意义上的翻版!这有什么问题呢?问题大了。这个内核没有办法给用户呈现一个原始的磁盘序列号,也就是序列号本身。为何不把处理留给应用程序呢?