leetcode283

1、Move Zeroes
Given an array nums, write a function to move all 0’s to the end of it while maintaining the relative order of the non-zero elements.
For example, given nums = [0, 1, 0, 3, 12], after calling your function, nums should be [1, 3, 12, 0, 0].
Note:
You must do this in-place without making a copy of the array.
Minimize the total number of operations.
第一个想法就是新建一个大小相同的数组,遍历一遍非零元素,按顺序放进去,剩余的用0补齐就好,然鹅题目不允许~
类似的,对于容器有很多方便的函数嘛~当遇到零时,删掉好了,然后count一下有多少零,最后再添加上嗯~

class Solution {
public:
    void moveZeroes(vector<int>& nums) {
        int count=0;
        int n=nums.size();
        for(int i=0;iif(!nums[i]){
                nums.erase (nums.begin()+i);
                count++;
                n--;
            }
            else
                i++;
            for(int i=0;i0);
    }
};

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