A proper vertex coloring is a labeling of the graph’s vertices with colors such that no two vertices sharing the same edge have the same color. A coloring using at most k colors is called a (proper) k-coloring.
Now you are supposed to tell if a given coloring is a proper k-coloring.
Input Specification:
Each input file contains one test case. For each case, the first line gives two positive integers N and M (both no more than 10
4
), being the total numbers of vertices and edges, respectively. Then M lines follow, each describes an edge by giving the indices (from 0 to N−1) of the two ends of the edge.
After the graph, a positive integer K (≤ 100) is given, which is the number of colorings you are supposed to check. Then K lines follow, each contains N colors which are represented by non-negative integers in the range of int. The i-th color is the color of the i-th vertex.
Output Specification:
For each coloring, print in a line k-coloring if it is a proper k-coloring for some positive k, or No if not.
Sample Input:
10 11
8 7
6 8
4 5
8 4
8 1
1 2
1 4
9 8
9 1
1 0
2 4
4
0 1 0 1 4 1 0 1 3 0
0 1 0 1 4 1 0 1 0 0
8 1 0 1 4 1 0 5 3 0
1 2 3 4 5 6 7 8 8 9
Sample Output:
4-coloring
No
6-coloring
注意:set容器能共自动过滤掉相同的元素
题目大意:
编号0-n-1的n个节点分别染上一种颜色,问是否满足同一条边的两个节点不同色.
分析:先将所有的边存下,在将所有节点的颜色存下(用set存颜色同时可以判断有多少种不同的颜色)。然后判断每条边的两个节点是否同色。
#include#include #include #pragma warning(disable:4996) using namespace std; int n, m, k; struct Node { int l, r; }e[10004]; int a[10002]; set c; int main() { cin >> n >> m; for (int i = 0; i < m; i++) cin >> e[i].l >> e[i].r; cin >> k; while (k--) { c.clear(); int flag = true; for (int i = 0; i < n; i++) { cin >> a[i]; c.insert(a[i]); } for (int i = 0; i < m; i++) { if (a[e[i].l] == a[e[i].r]) { flag = false; break; } } if (flag) { printf("%d-coloring\n", c.size()); } else { printf("No\n"); } } return 0; }