shell 扫描读取并替换某个词

#!/bin/bash

mode=$1
path=$2

basepath=$(cd `dirname $0`; pwd)

if [ ${path} == "./"  ]||[ ${path} == ${basepath} ];then
        echo "you can not do this operation in current path: ${basepath} "
        exit 1;
fi

if [ "-v" = ${mode} ];then
        echo "=========>these sh need to replace:"
        find ${path} -name "*.sh" | while read line
        do
                grep "return .*-1" ${line} &>/dev/null
                if [ $? -eq 0 ]; then
                        echo -e " this sh need replace :\033[36m ${line} \033[0m"
                fi
        done

        echo ============================ End ========================================
elif [ "-x" = ${mode} ];then
        echo =========begin replace sh at path: ${path} =============

        find ${path} -name "*.sh" | while read line
        do
                grep "return .*-1" ${line} &>/dev/null
                if [ $? -eq 0 ]; then
                        cp -a ${line} ${line}.bak
                        sed -i 's/return .*-1/return 1/g' ${line}
                        echo "you have replace this sh : ${line} ======>" >>replace_return.log
                        echo $( diff ${line} ${line}.bak ) >>replace_return.log
                        echo -e "you have replace this sh :\033[31m ${line} \033[0m"
                fi
        done
        echo ============================ End ========================================
else
        echo "please input like this: ./replace_return.sh -[v|x] [path]"
fi

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