本文由 Luzhuo 编写,转发请保留该信息.
原文: http://blog.csdn.net/Rozol/article/details/71156387
以下代码以Python3.6.1为例
Less is more!
#!/usr/bin/env python
# coding=utf-8
__author__ = 'Luzhuo'
__date__ = '2017/5/3'
# copydemo.py copy深和浅拷贝
# 深浅拷贝区别:
# 1.浅拷贝:创建新的复合对象,然后将'引用'拷贝到该复合对象中。
# 2.深拷贝:创建新的复合对象,然后'递归地将原始对象'拷贝到该复合对象中
import copy
class Ls:
def __init__(self, name):
self.name = name
@property
def setname(self, name):
self.name = name
def __str__(self):
return self.name
__repr__ = __str__
def __iter__(self):
return self
list_0 = ["A", "B", ["C", "D"], Ls("E")]
def demo():
# --- 浅拷贝的拷贝方式 ---
list_1 = copy.copy(list_0)
list_2 = list_0.copy()
list_3 = list_0[:]
list_4 = list(list_0)
# --- 深拷贝的拷贝方式 ---
lists_d = copy.deepcopy(list_0)
# --- 深浅拷贝的区别 ---
# 1. 对第一层数据进行赋值
list_0[0] = "X0"
list_1[0] = "X1"
list_2[0] = "X2"
list_3[0] = "X3"
list_4[0] = "X4"
lists_d[0] = "Xd"
# 打印结果: 理所当然,所有列表都发生了变化
# list_0: ['X0', 'B', ['C', 'D'], E]
# list_1: ['X1', 'B', ['C', 'D'], E]
# list_2: ['X2', 'B', ['C', 'D'], E]
# list_3: ['X3', 'B', ['C', 'D'], E]
# list_4: ['X4', 'B', ['C', 'D'], E]
# list_d: ['Xd', 'B', ['C', 'D'], E]
# 2. 对第二层的list引用进行赋值
list_0[2][0] = "Y0"
list_1[2][0] = "Y1"
list_2[2][0] = "Y2"
list_3[2][0] = "Y3"
list_4[2][0] = "Y4"
lists_d[2][0] = "Yd"
# 打印结果: 0-1都被改成了同一个值,这说明浅拷贝只拷贝了第二层list的引用;而深拷贝则拷贝了数据结构
# list_0: ['X0', 'B', ['Y4', 'D'], E]
# list_1: ['X1', 'B', ['Y4', 'D'], E]
# list_2: ['X2', 'B', ['Y4', 'D'], E]
# list_3: ['X3', 'B', ['Y4', 'D'], E]
# list_4: ['X4', 'B', ['Y4', 'D'], E]
# list_d: ['Xd', 'B', ['Yd', 'D'], E]
# 3. 对第三层的Ls对象引用进行赋值
list_0[3].name = "Z0"
list_1[3].name = "Z1"
list_2[3].name = "Z2"
list_3[3].name = "Z3"
list_4[3].name = "Z4"
lists_d[3].name = "Zd"
# 执行结果: 继续验证了上方论点
# list_0: ['X0', 'B', ['Y4', 'D'], Z4]
# list_1: ['X1', 'B', ['Y4', 'D'], Z4]
# list_2: ['X2', 'B', ['Y4', 'D'], Z4]
# list_3: ['X3', 'B', ['Y4', 'D'], Z4]
# list_4: ['X4', 'B', ['Y4', 'D'], Z4]
# list_d: ['Xd', 'B', ['Yd', 'D'], Zd]
print("list_0: {}".format(list_0))
print("list_1: {}".format(list_1))
print("list_2: {}".format(list_2))
print("list_3: {}".format(list_3))
print("list_4: {}".format(list_4))
print("list_d: {}".format(lists_d))
if __name__ == "__main__":
demo()