错误“json.decoder.JSONDecodeError: Unterminated string starting at: line 1 column 3520 (char 3519)”的解决

前几天在用requests和BeautifulSoup组合写爬虫，用BeautifulSoup解析网页的时候出现了一个错误，烦恼了可长时间，把错误输进网页也没找到解决方法，终于在无意间给解决了，写这个以防自己下次出现相同的错误，忘了怎么解决。

soup = BeautifulSoup(html.text,'lxml')
print(soup.text)
params = json.loads(soup.text)

代码只给出部分，不全公布

我是用json模块将字符串转换成字典来提取里面想要的数据

以下是显示的错误：

Traceback (most recent call last):
  File "D:/PythonProject/try.py", line 20, in
    params = json.loads(soup.text)
  File "D:\Anaconda3-5.2install\lib\json\__init__.py", line 354, in loads
    return _default_decoder.decode(s)
  File "D:\Anaconda3-5.2install\lib\json\decoder.py", line 339, in decode
    obj, end = self.raw_decode(s, idx=_w(s, 0).end())
  File "D:\Anaconda3-5.2install\lib\json\decoder.py", line 355, in raw_decode
    obj, end = self.scan_once(s, idx)
json.decoder.JSONDecodeError: Unterminated string starting at: line 1 column 3520 (char 3519)

错误的代码语句是：soup = BeautifulSoup(html.text,'lxml')

解决方法是：将这句改成soup = BeautifulSoup(html.text,'html.parser'),就是把‘lxml’换成“html.parser”就可以了