Python中的eval函数

代码版本：3.6.3    文档：3.6.6eval()

 eval()是Python内置函数，点进去是这样的

def eval(*args, **kwargs): # real signature unknown
    """
    Evaluate the given source in the context of globals and locals.
    
    The source may be a string representing a Python expression
    or a code object as returned by compile().
    The globals must be a dictionary and locals can be any mapping,
    defaulting to the current globals and locals.
    If only globals is given, locals defaults to it.
    """
    pass

 pycharm提示是这样的

 

eval()接收一个字符串格式的表达式参数，和两个可选参数globals和locals，如果给的话，global是必须是字典，locals可以是任何映射对象。返回表达式的结果。

可选参数其实是给一个寻找的范围，如果给的话，用位置传参格式，不能用关键字传参格式。如果不给定，则从locals()和globals()里寻找内容，返回表达式的结果。

 

例子：

没有globals和locals参数的：

def f():
    pass


class A:
    pass


a = A()

my_list = ['1', '1.0', '[2]', '(1,)', '{1,}', '{"k":"v"}', 'f', 'A', 'a']
for i in my_list:
    da = eval(i)
    print(da, type(da))


# 结果：
# 1 
# 1.0 
# [2] 
# (1,) 
# {1} 
# {'k': 'v'} 
#  
#  
# <__main__.A object at 0x000001DB6D98C320> 

 

有参数的：

def fa():
    print('func a is run')


def fb():
    print('func b is run')


g = {'fa': fb, 'fb': fa}

eval('fa')()
eval('fa', g)()


# 结果:
# func a is run
# func b is run

 

一直说是表达式，举个例子

def fa():
    return 3


g = {'a': 1}

print(eval('print(1)'))
print(eval('fa()'))
print(eval('a+1', g))


# 结果：
# 1
# None
# 3
# 2

 

注意，第一个参数必须是可执行的表达式，如果只是一个普通的字符串，那就报错

eval('tomorrow')
# Traceback (most recent call last):
#   File "E:x/x.py", line 1, in 
#     eval('tomorrow')
#   File "", line 1, in 
# NameError: name 'tomorrow' is not defined


eval('see you')
# Traceback (most recent call last):
#   File "E:x/x.py", line 10, in 
#     eval('see you')
#   File "", line 1
#     see you
#           ^
# SyntaxError: unexpected EOF while parsing

 

可选参数传入的话要注意，会改变你传入的字典本来的内容。文档：

If the globals dictionary is present and lacks ‘__builtins__’, the current globals are copied into globals before expression is parsed.