面试手写代码题目
二分查找
private static int binarySearch(int a[], int target) {
if (a == null || a.length == 0) return -1;
int left = 0, right = a.length - 1;
while (left <= right) {
int mid = (left + right) / 2;
if (a[mid] == target) return mid;
else if (a[mid] > target) right = mid - 1;
else left = mid + 1;
}
return -1;
}KMP
private static int[] getNext(char[] pattern) {
int[] next = new int[pattern.length + 1];
int i = 0, j = -1, len = pattern.length;
next[0] = -1;
while (i < len) {
if (j == -1 || pattern[i] == pattern[j]) {
i++;
j++;
next[i] = j;
} else {
j = next[j];
}
}
return next;
}
private static int kmp(char[] text, char[] pattern) {
if (text == null || text.length == 0
|| pattern == null || pattern.length == 0) return -1;
int[] next = getNext(pattern);
int i = 0, j = 0, len1 = text.length, len2 = pattern.length;
while (i < len1 && j < len2) {
if (j == -1 || text[i] == pattern[j]) {
i++;
j++;
} else {
j = next[j];
}
if (j == len2) {
// 返回出现模式串位置
return i - len2 + 1;
// 统计出现的次数
// j=next[j];
// ans++;
}
}
return -1;
}堆排序
private static void swap(int a[], int x, int y) {
int tmp = a[x];
a[x] = a[y];
a[y] = tmp;
}
private static void sift(int a[], int root, int hight) {
if (root >= hight) return;
int left = root * 2, right = left + 1;
if (left < hight && a[root] < a[left]) {
swap(a, root, left);
sift(a, left, hight);
}
if (right < hight && a[root] < a[right]) {
swap(a, root, right);
sift(a, right, hight);
}
}
private static void heapSort(int a[]) {
if (a == null || a.length == 0) return;
// init
int b[] = new int[a.length + 1];
for (int i = 1, len = b.length; i < len; i++) {
b[i] = a[i - 1];
}
// build max heap
for (int i = b.length / 2; i >= 1; i--) {
sift(b, i, b.length);
}
// sort
for (int i = 1, len = b.length; i < len; i++) {
swap(b, 1, len - i);
a[i-1] = b[len - i];
sift(b, 1, len - i);
}
}快速排序
private static void swap(int a[], int x, int y) {
int tmp = a[x];
a[x] = a[y];
a[y] = tmp;
}
private static void quickSort(int[] a) {
if (a == null || a.length == 0) return;
quickSort(a, 0, a.length - 1);
}
private static void quickSort(int[] a, int left, int right) {
if (left < right) {
int i = left, j = right;
int key = a[left];
while (i < j) {
while (i < j && a[j] >= key) {
j--;
}
if (i < j) {
swap(a, i, j);
i++;
}
while (i < j && a[i] <= key) {
i++;
}
if (i < j) {
swap(a, i, j);
j--;
}
}
a[i] = key;
quickSort(a, left, i - 1);
quickSort(a, i + 1, right);
}
}
private void quickSort(int a[]) {
if (a == null || a.length == 0) return;
quickSort(a, 0, a.length - 1);
}快速排序非递归版
private static void swap(int a[], int x, int y) {
int tmp = a[x];
a[x] = a[y];
a[y] = tmp;
}
private static int quickSort(int[] a, int left, int right) {
int i = left, j = right;
int key = a[left];
while (i < j) {
while (i < j && a[j] >= key) {
j--;
}
if (i < j) {
swap(a, i, j);
i++;
}
while (i < j && a[i] <= key) {
i++;
}
if (i < j) {
swap(a, i, j);
j--;
}
}
a[i] = key;
return i;
}
private static class Status {
int left, right;
public Status(int left, int right) {
this.left = left;
this.right = right;
}
public int getLeft() {
return left;
}
public int getRight() {
return right;
}
}
private static void quickSort(int a[]) {
if (a == null || a.length == 0) return;
Stack stack = new Stack<>();
int left = 0, right = a.length - 1;
stack.push(new Status(left, right));
while (!stack.empty()) {
Status currStatus = stack.pop();
int partitionPos = -1;
if (currStatus.getLeft() >= currStatus.getRight()) continue;
partitionPos = quickSort(a, currStatus.getLeft(), currStatus.getRight());
if (partitionPos == -1) continue;
if (currStatus.getLeft() < partitionPos - 1) {
stack.push(new Status(currStatus.getLeft(), partitionPos - 1));
}
if (partitionPos + 1 < currStatus.getRight()) {
stack.push(new Status(partitionPos + 1, currStatus.getRight()));
}
}
} Dijkstra
private static int Dijkstra(int map[][], int start, int end) {
if (map == null || map.length == 0 || map[0].length == 0) return -1;
int dis[] = new int[map.length];
boolean vis[] = new boolean[map.length];
for (int i = 0, len = map.length; i < len; i++) {
dis[i] = map[start][i];
vis[i] = false;
}
for (int i = 0, len = map.length; i < len - 1; i++) {
int minx = Integer.MAX_VALUE, k = -1;
for (int j = 0; j < len; j++) {
if (!vis[j] && dis[j] < minx) {
minx = dis[j];
k = j;
}
}
if (k == -1) return -1;
else {
vis[k] = true;
for (int j = 0; j < len; j++) {
if (!vis[j] && dis[j] < dis[k] + map[k][j]) {
dis[j] = dis[k] + map[k][j];
}
}
}
}
return dis[end] == Integer.MAX_VALUE ? -1 : dis[end];
}Floyd
private static int Floyd(int map[][], int start, int end) {
if (map == null || map.length == 0 || map[0].length == 0) return -1;
int dp[][] = new int[map.length][map[0].length];
for (int i = 0, len = map.length; i < len; i++) {
for (int j = i; j < len; j++) {
dp[i][j] = map[i][j] == -1 ? Integer.MAX_VALUE : map[i][j];
}
}
for (int k = 0, len = map.length; k < len; k++) {
for (int i = 0; i < len; i++) {
for (int j = 0; j < len; j++) {
dp[i][j] = Math.min(dp[i][j], dp[i][k] + dp[k][j]);
}
}
}
return dp[start][end];
}最长公共子序列
private static int LCS(String a, String b) {
if (a == null || b == null || "".equals(a) || "".equals(b)) return -1;
int dp[][] = new int[a.length()][b.length()];
for (int i = 1, lena = a.length(); i <= lena; i++) {
for (int j = 1, lenb = b.length(); j <= lenb; j++) {
char cha = a.charAt(i - 1);
char chb = b.charAt(j - 1);
if (cha == chb) {
dp[i][j] = dp[i - 1][j - 1] + 1;
} else {
dp[i][j] = Math.max(dp[i - 1][j], dp[i][j - 1]);
}
}
}
return dp[a.length()][b.length()];
}最小编辑距离
private static int Levenshtein(String a, String b) {
if (a == null || b == null || "".equals(a) || "".equals(b)) return -1;
int dp[][] = new int[a.length()][b.length()];
for (int i = 0, lena = a.length(); i < lena; i++) {
dp[i][0] = i;
}
for (int i = 0, lenb = b.length(); i < lenb; i++) {
dp[0][i] = i;
}
for (int i = 1, lena = a.length(); i <= lena; i++) {
for (int j = 1, lenb = b.length(); j <= lenb; j++) {
char cha = a.charAt(i - 1);
char chb = b.charAt(j - 1);
int cost = 1;
if (cha == chb) {
cost = 0;
}
dp[i][j] = Math.min(Math.min(dp[i - 1][j] + 1, dp[i][j - 1] + 1), dp[i - 1][j - 1] + cost);
}
}
return dp[a.length()][b.length()];
}最长回文子串
public class Palindrome {
public int getLongestPalindrome(String A, int n) {
// write code here
boolean isPalindrome[][] = new boolean[n][n];
int ans = 0;
for (int i = n - 1; i >= 0; i--) {
isPalindrome[i][i] = true;
for (int j = i + 1; j < n; j++) {
if (j == i + 1) {
isPalindrome[i][j] = A.charAt(i) == A.charAt(j);
} else {
isPalindrome[i][j] = isPalindrome[i + 1][j - 1] && A.charAt(i) == A.charAt(j);
}
if (isPalindrome[i][j]) {
ans = Math.max(ans, j - i + 1);
}
}
}
return ans;
}
}最长递增子序列
private static int solve(int a[]) {
int dp[] = new int[a.length];
for (int i = 0, len = a.length; i < len; i++) {
dp[i] = 1;
for (int j = i - 1; j >= 0; j--) {
if (a[j] < a[i]) {
dp[i] = Math.max(dp[i], dp[j] + 1);
}
}
}
int ans = 0;
for (int i = 0, len = a.length; i < len; i++) {
ans = Math.max(dp[i], ans);
}
return ans;
}最长公共子序列
public class LCS {
public int findLCS(String A, int n, String B, int m) {
// write code here
int dp[][] = new int[n + 1][m + 1];
for (int i = 0; i <= n; i++) {
for (int j = 0; j <= m; j++) {
dp[i][j] = 0;
}
}
for (int i = 1; i <= n; i++) {
for (int j = 1; j <= m; j++) {
if (A.charAt(i - 1) == B.charAt(j - 1)) {
dp[i][j] = Math.max(dp[i][j], dp[i - 1][j - 1] + 1);
} else {
dp[i][j] = Math.max(dp[i - 1][j], dp[i][j - 1]);
}
}
}
return dp[n][m];
}
}