Java:使用接口来实现排序(按照年龄或分数)

//封装一个排序类
package com.lanou.jk;
public interface Sort {
//规则
public int sort(Object obj,Object obj1);
}

class Test {
    //接收用户定义的排序规则的类
    public Sort s;
    public Test(Sort s){
        this.s = s;//不写无参数的意味着必须给个s否则不能用
    }
    public Object[] paixu(Object[] obj){
        for (int i = 0; i < obj.length - 1; i++) {
            for (int j = 0; j < obj.length - i - 1; j++) {
                //判断大小
                int result = s.sort(obj[j], obj[j+1]);
                 if (result > 0) {  
                    Object temp = obj[j];
                    obj[j] = obj[j+1];
                    obj[j+1] = temp;
                }
                //交换 
            }
            
        }
        return obj;
    }

}
//用户类
package com.lanou.jk;

import java.util.Arrays;

public class User {
public static void main(String[] args) {
//数据
Cat c = new Cat();
c.age = 12;
c.score = 99;

    Cat c1 = new Cat();
    c1.age = 4;
    c1.score = 55;
    
    Cat c2 = new Cat();
    c2.age = 9;
    c2.score = 88;
    
    Cat c3 = new Cat();
    c3.age = 21;
    c3.score = 85;

        //创建一个数组
        Cat[] arr = {c,c1,c2,c3};
        //创建test接收的类
        com cm= new com();
        Test test = new Test(cm);
        //接收排序的结果
        Object[] newArr = test.paixu(arr);
        //打印输出
        System.out.println(Arrays.toString(newArr));

}

}
//Sort接口的实现类
class com implements Sort {
@Override
public int sort(Object obj, Object obj1) {

        //强转转换类型
        Cat c = (Cat)obj;
        Cat c1 = (Cat)obj1;
        //利用Sort方法进行比较
        if (c.score > c1.score) {
            return 1;
        }   
        return -1;
    }

}
//数据类
class Cat{
int age;
int score;
@Override
public String toString() {
// TODO Auto-generated method stub
return "年龄 = "+ this.age + "分数"+ this.score;
}
}