Python在网站爬取所有图片链接并判断其状态值

#coding:utf-8

import urllib

from bs4 import BeautifulSoup

import urllib2

for pa in range(1,200):

url = "http://www.xxxxx.com/page/{}".format(pa)

html = urllib.urlopen(url).read()

soup = BeautifulSoup(html, "html.parser")

imglist = soup.find_all("img")

lenth = len(imglist)

for i in range(lenth):

Pictu = imglist[i].attrs['src']

req = urllib2.Request(Pictu)

response = None

try:

response = urllib2.urlopen(req, timeout=5)

print response.geturl()

print response.getcode()

except urllib2.URLError as e:

print e

if hasattr(e, 'code'):

print e.geturl()

print 'Error code:', e.code

print e.info

elif hasattr(e, 'reason'):

print 'Reason:', e.reason

except:

pass

finally:

if response:

response.close()

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初次编写此代码，实现在网站爬取所有图片（翻页），并判断其状态值，若有错误，欢迎指正！

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