这个作业属于哪个课程 | C语言作业计科四班 |
---|---|
这个作业要求在哪里 | https://edu.cnblogs.com/campus/zswxy/CST2019-4/homework/10277 |
这个作业的目标 | 学习用上次作业代码编写出答案 |
作业正文 | 看下面内容 |
其他参考文献 | https://m.wenda.so.com/q/1378547425075728 |
2.2 设计思路和遇到的问题
设计思路:其实利用上次代码进行加工,在百度一下%g和rand()如何结合运用以及他们各自的用法,在自己琢磨一下。
遇到的问题:其实运用上次代码可以快速编写出一二年级的答案,但是三年级是怎么也是错误的,不知道哪里出现了问题,所以花费了很多时间。
2.2.3 程序结果截图
2.2.4 程序代码
#include
#include
#include
#include
void menu();
void help();
void error();
void operation_1(); void one_1();
void operation_2(); void two_2();
void operation_3(); void three_3();
int main()
{
int n;
printf("========== 口算生成器 ==========\n");
printf("欢迎使用口算生成器 :\n");
printf("\n");
printf("\n");
help();
while(1)
{
menu();
scanf("%d",&n);
switch(n)
{
case 1:operation_1();break;
case 2:operation_2();break;
case 3:operation_3();break;
case 4:help();break;
}
printf("\n");
if(n==5) break;
if(n>5||n<1) error();
}
return 0;
}
void help()
{
printf("帮助信息\n");
printf("您需要输入命令代号来进行操作\n");
printf("一年级题目为不超过十位的加减法\n");
printf("二年级题目为不超过百位的乘除法\n");
printf("三年级题目为不超过百位的加减乘除混合题目\n");
printf("\n");
}
void menu()
{
printf("操作列表:\n1)一年级 2)二年级 3)三年级\n");
printf("4)帮助 5)退出程序\n请输入代号:");
printf("\n");
}
void error()
{
printf("操作错误 请重新输入 ");
printf("\n");
printf("\n");
}
void operation_1()
{
printf("请输入题目数量>");
one_1();
}
void operation_2()
{
printf("请输入题目数量>");
two_2();
}
void operation_3()
{
printf("请输入题目数量>");
three_3();
}
void one_1()
{
int n,a,b,c,x;
time_t t;
scanf("%d",&n);
printf("一年级题目如下:\n");
srand((unsigned)time(NULL));
for(int i=1;i<=n;i++)
{
a=rand()%10+1;
b=rand()%10+1;
c=rand()%2;
if(c==0)
{
x=a+b;
printf("%d + %d = %d\n",a,b,x);
}
else
{
x=a-b;
printf("%d - %d = %d\n",a,b,x);
printf("\n");
}
}
}
void two_2()
{
int n,d,e,f;
float z;
time_t t;
scanf("%d",&n);
printf("二年级题目如下:\n");
srand((unsigned)time(NULL));
for(int i=1;i<=n;i++)
{
d=rand()%100;
e=rand()%100;
f=rand()%2;
if(f==0)
{
z=d*e;
printf("%d * %d = %g\n",d,e,z);
}
else
{
while(e==0)
{
e=rand() % 100;
}
z=d/(e*1.0);
printf("%d / %d = %g\n",d,e,z);
printf("\n");
}
}
}
void three_3()
{
int n,h,k,j;
float s;
char fh1[2],fh2[2];
time_t t;
scanf("%d",&n);
printf("三年级题目如下:\n");
srand((unsigned)time(NULL));
char fh[4][6] = {"*","/","+","-"};
for(int i=1;i<=n;i++)
{
h=rand()%100;
k=rand()%100;
j=rand()%100;
while (h==0||k==0||j==0)
{
h=rand() % 100;k=rand() % 100;j=rand() % 100;
}
strcpy(fh1,fh[rand() % 3]);
strcpy(fh2,fh[rand() % 3]);
if(strcmp(fh1,"*")==0&&strcmp(fh2,"*")==0)
{
s = h * k * j;
printf("%2d %s %2d %s %2d = %g\n",h,fh1,k,fh2,j,s);
}
else if(strcmp(fh1,"*")==0&&strcmp(fh2,"/")==0)
{
s = h * k / (j*1.0);
printf("%2d %s %2d %s %2d = %g\n",h,fh1,k,fh2,j,s);
}
else if(strcmp(fh1,"*")==0&&strcmp(fh2,"+")==0)
{
s = h * k + j;
printf("%2d %s %2d %s %2d = %g\n",h,fh1,k,fh2,j,s);
}
else if(strcmp(fh1,"*")==0&&strcmp(fh2,"-")==0)
{
s = h * k - j;
printf("%2d %s %2d %s %2d = %g\n",h,fh1,k,fh2,j,s);
}
else if(strcmp(fh1,"/")==0&&strcmp(fh2,"+")==0)
{
s = h / (k*1.0) + j;
printf("%2d %s %2d %s %2d = %g\n",h,fh1,k,fh2,j,s);
}
else if(strcmp(fh1,"/")==0&&strcmp(fh2,"-")==0)
{
s = h / (k*1.0) - j;
printf("%2d %s %2d %s %2d = %g\n",h,fh1,k,fh2,j,s);
}
else if(strcmp(fh1,"/")==0&&strcmp(fh2,"/")==0)
{
s = h / (k*1.0) / (j*1.0);
printf("%2d %s %2d %s %2d = %g\n",h,fh1,k,fh2,j,s);
}
else if(strcmp(fh1,"+")==0&&strcmp(fh2,"-")==0)
{
s = h + k - j;
printf("%2d %s %2d %s %2d = %g\n",h,fh1,k,fh2,j,s);
}
else if(strcmp(fh1,"+")==0&&strcmp(fh2,"+")==0)
{
s = h + k + j;
printf("%2d %s %2d %s %2d = %g\n",h,fh1,k,fh2,j,s);
}
else if(strcmp(fh1,"-")==0&&strcmp(fh2,"-")==0)
{
s = h - k - j;
printf("%2d %s %2d %s %2d = %g\n",h,fh1,k,fh2,j,s);
}
else if(strcmp(fh1,"/")==0&&strcmp(fh2,"*")==0)
{
s = h / (k*1.0) * j;
printf("%2d %s %2d %s %2d = %g\n",h,fh1,k,fh2,j,s);
}
else if(strcmp(fh1,"+")==0&&strcmp(fh2,"/")==0)
{
s = h + k / (j*1.0);
printf("%2d %s %2d %s %2d = %g\n",h,fh1,k,fh2,j,s);
}
else if(strcmp(fh1,"+")==0&&strcmp(fh2,"*")==0)
{
s = h + k * j;
printf("%2d %s %2d %s %2d = %g\n",h,fh1,k,fh2,j,s);
}
else if(strcmp(fh1,"-")==0&&strcmp(fh2,"/")==0)
{
s = h - k / (j*1.0);
printf("%2d %s %2d %s %2d = %g\n",h,fh1,k,fh2,j,s);
}
else if(strcmp(fh1,"-")==0&&strcmp(fh2,"+")==0)
{
s = h - k + j;
printf("%2d %s %2d %s %2d = %g\n",h,fh1,k,fh2,j,s);
}
else if(strcmp(fh1,"-")==0&&strcmp(fh2,"*")==0)
{
s = h - k * j;
printf("%2d %s %2d %s %2d = %g\n",h,fh1,k,fh2,j,s);
}
}
}
2.2.5 Gitee上传截图与链接
链接:
https://gitee.com/xie_xiang_yun/cxiexiangyun.git