程序员大佬直播C语言写个贪吃蛇游戏练手,如此简单,你会做了吗

用C语言完成简单经典小游戏——贪吃蛇。出格适合新手熟谙CC语言。

首要触及C语言常识点以下:

*布局体,函数的定义及调用,指针变量,指针和数组,逻辑表达式,根基的选择和轮回语句,头文件的编写等*。

可以说是麻雀虽小,五脏俱全,是新手演习C措辞的绝佳小项目!

游戏界面以下:

程序员大佬直播C语言写个贪吃蛇游戏练手,如此简单,你会做了吗_第1张图片

根基思路:

蛇每吃一个食品蛇身子就增加一格,用WASD节制蛇头的勾当,而蛇身子跟着蛇头走,每后一格蛇身子下一步走到上一格蛇身子的位置,以此类推。

法度典型首要变量以下:

```

#define M 20//全数图形界面的长和宽

#define N 60

struct snake a[(M - 2)*(N - 2)];//蛇身数组

int snake_x =4;//蛇身的XY坐标

int snake_y =4;

int X = 1;//节制蛇头的偏向量

int Y = 0;

int food_x , food_y ;//食品的XY坐标

int score = 0;//分数

```

食品的随机位置产生是经过过程两个随机数辨别代表X,Y坐标完成的。

```

void food(int *x, int *y,int *fx,int *fy,int *s, struct snake *snake)

{

int ffx, ffy;//上一次食品的XY坐标

ffx = *fx;

ffy = *fy;

if (*x == *fx && *y == *fy)//假定吃到了食品,产生下一个食品

{

do {

*fx = 1 + rand() % (N - 3);

*fy = 1 + rand() % (M - 3);

} while (ffx == *fx && ffy == *fy);//包管与前次食品位置不合

for (int i= (*s); i >= 0; i--)

{

if ((snake + *s)->snake_x == *fx && (snake + *s)->snake_y == *fy) {

*fx = 1 + rand() % (N - 3);

*fy = 1 + rand() % (M - 3);

}

}//大年夜大年夜概率包管食品与蛇身子的位置不合(不克不及完全包管)

(*s)++ ; //分数加一!!!!!!!

}

}

```

用WASD节制蛇头的勾当是经过过程改动蛇头的X,Y坐标完成的。

```

程序员大佬直播C语言写个贪吃蛇游戏练手,如此简单,你会做了吗_第2张图片

void control(int *x,int *y,int *X,int *Y)//xy是蛇头的坐标,XY是节制勾当偏向的量

{

if (_kbhit())

{

switch (_getch())

{

case 'w' :

case 'W' :

if(interf[*y - 1][*x]!='@'){ //if语句包管蛇不克不及倒着走

*X = 0; *Y = -1;

}

break;

case 'd':

case 'D':

if(interf[*y][*x + 1] != '@'){

*X = 1; *Y = 0;

}

break;

case 's':

case 'S':

if (interf[*y + 1][*x] != '@') {

*X = 0; *Y = 1;

}

break;

case 'a':

case 'A':

if (interf[*y][*x - 1] != '@') {

*X = -1; *Y = 0;

}

break;

default:

break;

}

}

*x = *x + *X;//改动一次位置

*y = *y + *Y;

}

```

用定义蛇身子的布局体储藏身安身子的XY坐标,然后定义蛇身子布局体数组存储每节蛇身子。

```

struct snake

{

int number;

int snake_x;

int snake_y;

//struct snake *next;

};

struct snake a[(M - 2)*(N - 2)];

void build_snake(struct snake *snake,int s,int *sx,int *sy)//sx,sy蛇头的位置

{

for (int i = s; i >= 0; i--)

{

if (i == 0) {

(snake + i)->number = i;

(snake + i)->snake_x = *sx;

(snake + i)->snake_y = *sy;

}else{

(snake + i)->number = i;

(snake + i)->snake_x = (snake + i - 1)->snake_x;

(snake + i)->snake_y = (snake + i - 1)->snake_y;

}

}

}

```

有了蛇身子和食品的坐标位置,将它们一路存储在一个暗示全数界面的二位数组,然后轮回打印全数数组构成动画成果!

```

char interf[M][N];

void newinterface(struct snake *snake, int fx, int fy,int s)

{

int x, y;

for (int i = 0; i < M; i++)

{

for (int j = 0; j < N; j++)

{

if (i == 0 || i == M - 1)

interf[i][j] = '-';

//printf("-");

else if (j == 0)

interf[i][j] = '|';

//printf("|");

else if (j == N - 1)

interf[i][j] = '|';

//printf("| ");

else if (i == fy && j == fx)

interf[i][j] = '$';

//printf("$");

else

interf[i][j] = ' ';

//printf(" ");

}

}

for (; s >= 0; s--)

{

x = (snake + s)->snake_x;

y = (snake + s)->snake_y;

interf[y][x] = '@';

}

}

```

完全法度典型代码!!!

```

文件 snakemain.cpp

#include

#include

#include

#include "interface.h"

#include "snake.h"

int main(void)

{

struct snake a[(M - 2)*(N - 2)];

int snake_x =4;

int snake_y =4;

int X = 1;

int Y = 0;

int food_x , food_y ;

int score = 0;

do {

food_x = 1 + rand() % (N - 3);

food_y = 1 + rand() % (M - 3);

} while (food_x == 4 && food_y == 4);

for (;;)

{

system("cls");

printf(" 贪吃蛇小游戏");

printf(" 作者:xhyang 博客地址:http://blog.csdn.net/weixin_39449570 ");

printf("按W节制向上勾当,按D节制向右勾当,按S节制向下勾当,按A节制向左勾当。 ");

printf("得分:%d",score);

printf(" ");

control(&snake_x, &snake_y,&X,&Y);

build_snake(a, score, &snake_x, &snake_y);

death(snake_x, snake_y,score);

newinterface(a, food_x, food_y, score);

food(&snake_x, &snake_y, &food_x, &food_y,&score,a);

draw();

Sleep(140);

}

system("pause");

return 0;

}

```

```

文件 snake.h

#ifndef SNAKE_H

#define SNAKE_H

struct snake

{

int number;

int snake_x;

int snake_y;

//struct snake *next;

};

void build_snake(struct snake *snake, int s, int *sx, int *sy);

#endif

```

```

文件 snake.cpp

#include

#include

#include "snake.h"

void build_snake(struct snake *snake,int s,int *sx,int *sy)

{

for (int i = s; i >= 0; i--)

{

if (i == 0) {

(snake + i)->number = i;

(snake + i)->snake_x = *sx;

(snake + i)->snake_y = *sy;

}else{

(snake + i)->number = i;

(snake + i)->snake_x = (snake + i - 1)->snake_x;

(snake + i)->snake_y = (snake + i - 1)->snake_y;

}

}

}

```

```

文件 interface.h

#ifndef INTERFACE_H

#define INTERFACE_H

#define M 20

#define N 60

void control(int *x, int *y, int *X, int *Y);

void snake(int x, int y);

void newinterface(struct snake *snake, int fx, int fy, int s);

void food(int *x, int *y, int *fx, int *fy, int *s, struct snake *snake);

void draw(void);

void death(int x, int y, int s);

#endif

```

```

文件 interface.cpp

#include

#include

#include

#include

#include "interface.h"

#include "snake.h"

char interf[M][N];

void newinterface(struct snake *snake, int fx, int fy,int s)

{

int x, y;

for (int i = 0; i < M; i++)

{

for (int j = 0; j < N; j++)

{

if (i == 0 || i == M - 1)

interf[i][j] = '-';

//printf("-");

else if (j == 0)

interf[i][j] = '|';

//printf("|");

else if (j == N - 1)

interf[i][j] = '|';

//printf("| ");

else if (i == fy && j == fx)

interf[i][j] = '$';

//printf("$");

else

interf[i][j] = ' ';

//printf(" ");

}

}

for (; s >= 0; s--)

{

x = (snake + s)->snake_x;

y = (snake + s)->snake_y;

interf[y][x] = '@';

}

}

void food(int *x, int *y,int *fx,int *fy,int *s, struct snake *snake)

{

int ffx, ffy;//上一次食品的XY坐标

ffx = *fx;

ffy = *fy;

if (*x == *fx && *y == *fy)//假定吃到了食品,产生下一个食品

{

do {

*fx = 1 + rand() % (N - 3);

*fy = 1 + rand() % (M - 3);

} while (ffx == *fx && ffy == *fy);//包管与前次食品位置不合

for (int i= (*s); i >= 0; i--)

{

if ((snake + *s)->snake_x == *fx && (snake + *s)->snake_y == *fy) {

*fx = 1 + rand() % (N - 3);

*fy = 1 + rand() % (M - 3);

}

}//大年夜大年夜概率包管食品与蛇身子的位置不合(不克不及完全包管)

(*s)++ ; //分数加一!!!!!!!

}

}

void control(int *x,int *y,int *X,int *Y)//xy是蛇头的坐标,XY是节制勾当偏向的量

{

if (_kbhit())

{

switch (_getch())

{

case 'w' :

case 'W' :

if(interf[*y - 1][*x]!='@'){ //if语句包管蛇不克不及倒着走

*X = 0; *Y = -1;

}

break;

case 'd':

case 'D':

if(interf[*y][*x + 1] != '@'){

*X = 1; *Y = 0;

}

break;

case 's':

case 'S':

if (interf[*y + 1][*x] != '@') {

*X = 0; *Y = 1;

}

break;

case 'a':

case 'A':

if (interf[*y][*x - 1] != '@') {

*X = -1; *Y = 0;

}

break;

default:

break;

}

}

*x = *x + *X;//改动一次位置

*y = *y + *Y;

}

void draw(void)

{

for (int i = 0; i < M; i++)

{

for (int j = 0; j < N; j++)

{

printf("%c", interf[i][j]);

}

printf(" ");

}

}

void death(int x,int y,int s)

{

if (x == 0 || x == N-1 || y == 0 || y == M-1 || interf[y][x] == '@') {

for (;;)

{

system("cls");

printf(" 游戏中断! ");

printf(" 终究得分:%d ", s);

Sleep(140);

//system("pause");

}

}

}

程序员大佬直播C语言写个贪吃蛇游戏练手,如此简单,你会做了吗_第3张图片

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