1.编写一个简单程序,要求数组长度为5,静态赋值10,20,30,40,50,在控制台输出该数组的值。
package ssg; public class bat { public static void main(String[] args) { // TODO Auto-generated method stub int[] arr = { 10, 20, 30, 40, 50 }; for (int i = 0; i < 5; i++) { System.out.println(arr[i]); } } }
2.编写一个简单程序,要求数组长度为5,动态赋值10,20,30,40,50,在控制台输出该数组的值。
package ssg; public class bat { public static void main(String[] args) { // TODO Auto-generated method stub int[] arr = new int[5]; arr[0] = 10; arr[1] = 20; arr[2] = 30; arr[3] = 40; arr[4] = 50; for (int i = 0; i < 5; i++) { System.out.println(arr[i]); } } }
3.编写一个简单程序,定义整型数组,里面的元素是{23,45,22,33,56},求数组元素的和、平均值
package ssg; public class bat { public static void main(String[] args) { // TODO Auto-generated method stub int[] arr = { 23, 45, 22, 33, 56 }; int sum, average; sum = arr[0] + arr[1] + arr[2] + arr[3] + arr[4]; average = (arr[0] + arr[1] + arr[2] + arr[3] + arr[4]) / 5; System.out.println("数组元素的和为" + sum); System.out.println("平均值为" + average); } }
4.在一个有8个整数(18,25,7,36,13,2,89,63)的数组中找出其中最大的数及其下标
package Svd; public class bbt { public static void main(String[] args) { // TODO Auto-generated method stub int[] arr = { 18, 25, 7, 36, 13, 2, 89, 63 }; int max = arr[0], a = 0; for (int i = 1; i < arr.length; i++) { if (arr[i] > max) { max = arr[i]; a = i; } } System.out.println("数组中的最大值是:" + max); System.out.println("坐标为" + a); } }
5. 将一个数组中的元素逆序存放(知识点:数组遍历、数组元素访问)
package Svd; public class bbt { public static void main(String[] args) { // TODO Auto-generated method stub int arr[] = new int[] { 10, 20, 30, 40, 50 }; for (int i = 4; i >= 0; i--) { System.out.println(arr[i]); } } }
6、有一个已经排好序的数组。现输入一个数,要求按原来的规律将它插入数组中。(知识点:数组遍历、数组元素访问)