PAT (Advanced Level) Practice 1027

1027 Colors in Mars (20)（20 point(s)）

People in Mars represent the colors in their computers in a similar way as the Earth people. That is, a color is represented by a 6-digit number, where the first 2 digits are for Red, the middle 2 digits for Green, and the last 2 digits for Blue. The only difference is that they use radix 13 (0-9 and A-C) instead of 16. Now given a color in three decimal numbers (each between 0 and 168), you are supposed to output their Mars RGB values.

Input

Each input file contains one test case which occupies a line containing the three decimal color values.

Output

For each test case you should output the Mars RGB value in the following format: first output "#", then followed by a 6-digit number where all the English characters must be upper-cased. If a single color is only 1-digit long, you must print a "0" to the left.

Sample Input

15 43 71

Sample Output

#123456

题意：

    原本由16进制代表颜色，现在由13进制代表颜色分别是0-9,ABC。现在要求输入3个整数，转化为13进制，然后输出，如果转换后只有一个数，那么加上前导0.

C++：

#include
char radix[] = {'0', '1', '2', '3', '4', '5', '6', 
				'7', '8', '9', 'A', 'B', 'C'};
				
void transform(int c, int color, char ans[]){
	while(color){
		ans[c--] = radix[color % 13];
		color /= 13;
	}
}
int main(){
	int d_r,d_b,d_g;//十进制RBG 
	scanf("%d%d%d", &d_r, &d_b, &d_g);
	char ans[] = {'0', '0', '0', '0', '0', '0'};
	transform(1, d_r, ans);
	transform(3, d_b, ans);
	transform(5, d_g, ans);
	printf("#");
	for(int i = 0;i < 6;i++){
		printf("%c", ans[i]);
	}
	return 0;
}