Java实现——查找数组中连续元素的和等于给定数的子数组

转自几个面试经典算法题Java解答（http://www.cnblogs.com/sunniest/p/4596182.html）题目二

//给出一个排序好的数组和一个数，求数组中连续元素的和等于所给数的子数组

public class SubArraySum {
	public void findSubArraySum(int[] array , int sum){
		if(array == null || array.length == 0){
			System.out.println("array is empty.");
			return;
		}
		for(int i = 0 ; i < array.length ; i++){
			int temp = 0;
			for(int j = i ; j < array.length ; j++){
				temp += array[j];
				if(temp < sum){					
					continue;
				}else if(temp == sum){
					for(int k = i ; k <= j ; k++){
						System.out.print(array[k] + " ");
					}	
					System.out.println();
					break;
				}else{
					break;
				}
			}
		}
	}

    public void findSubArraySum2(int[] a , int n){
        if(a == null || a.length == 0){
            return;
        }
        int start = 0 , end = 0;
        for(int i = 0 ; i < a.length ; i++){
            int sum = a[i];
            start = i;
            end = i;
            for(int k = i + 1 ; k < a.length && sum < n ; k++){
                sum += a[k];
                end = k;
            }
            if(sum == n){
                for(int j = start ; j <=end ; j++){
                    System.out.print(a[j] + " ");
                }
                return;
            }
        }
        System.out.println("No such sub array exists.");        
    }

public static void main(String[] args) {SubArraySum sa = new SubArraySum();int[] a = {1,2,3,4,5,6};sa.findSubArraySum(a, 6);}}