Leetcode 之 Intersection of Two Arrays II

题目描述：
Given two arrays, write a function to compute their intersection.

Example:
Given nums1 = [1, 2, 2, 1], nums2 = [2, 2], return [2, 2].

Note:
Each element in the result should appear as many times as it shows in both arrays.
The result can be in any order.

简单题，不多说了，一个hashmap存nums1的状态， 另一个存储nums2 的， 遍历找到都存在的key值返回

代码：

public class Solution {
    public int[] intersect(int[] nums1, int[] nums2) {
        int[]insct;
            ArrayListtempList=new ArrayList();
            HashMapmap1=new HashMap(),map2=new HashMap(),map_temp,map_temp2;
            for(int n:nums1){
                if(map1.containsKey(n)){
                    map1.put(n, map1.get(n)+1);
                }
                else
                    map1.put(n,1);
            }
            for(int n:nums2){
                if(map2.containsKey(n)){
                    map2.put(n, map2.get(n)+1);
                }
                else
                    map2.put(n,1);
            }
            if(map1.size()>map2.size()){
                map_temp=map2;
                map_temp2=map1;
            }
            else
            {
                map_temp=map1;
                map_temp2=map2;
            }
            int times;
            for(int n:map_temp.keySet()){
                if(!map_temp2.containsKey(n))continue;
//              System.out.println(map_temp2.containsKey(n)+" "+n);
                times=Math.min(map_temp.get(n),map_temp2.get(n));
                for(int i=0;inew int[tempList.size()];
            for(int i=0;iget(i);
            }
            return insct;
    }
}