Leetcode题解 350. Intersection of Two Arrays II

Given two arrays, write a function to compute their intersection.

Example:
Given nums1 = [1, 2, 2, 1], nums2 = [2, 2], return [2, 2].

Note:
Each element in the result should appear as many times as it shows in both arrays.
The result can be in any order.

参照《程序员面试金典》字符串那章,有类似的题目。
这道题http://blog.csdn.net/xd_yu/article/details/51705646的升级版,也很简单。

public class Solution {

    public int[] intersect(int[] nums1, int[] nums2) {
        int len=100000;
        int[] temp1=new int[len];
        int[] temp2=new int[len];
        int[] temp=new int[len];
        for(int i=0;ifor(int i=0;iint count=0;
        for(int i=0;iif(temp1[i]!=0&&temp2[i]!=0){
               temp[i]=temp1[i]>temp2[i]?temp2[i]:temp1[i];
               count+=temp[i];
            }
        }
        int[] result=new int[count];
        int pos=0;
         for(int i=0;iif(temp1[i]!=0&&temp2[i]!=0){
                for(int j=0;jreturn result;
    }
}

你可能感兴趣的:(Leetcode题解,leetcode)