hdu 5948 Thickest Burger 2016ACM/ICPC沈阳赛区现场赛A

Problem Description

ACM ICPC is launching a thick burger. The thickness (or the height) of a piece of club steak is A (1 ≤ A ≤ 100). The thickness (or the height) of a piece of chicken steak is B (1 ≤ B ≤ 100). 
The chef allows to add just three pieces of meat into the burger and he does not allow to add three pieces of same type of meat. As a customer and a foodie, you want to know the maximum total thickness of a burger which you can get from the chef. Here we ignore the thickness of breads, vegetables and other seasonings.

 

Input

The first line is the number of test cases. For each test case, a line contains two positive integers A and B.

 

Output

For each test case, output a line containing the maximum total thickness of a burger.

 

Sample Input

10 68 42 1 35 25 70 59 79 65 63 46 6 28 82 92 62 43 96 37 28

 

Sample Output

178 71 165 217 193 98 192 246 235 102

Hint

Consider the first test case, since 68+68+42 is bigger than 68+42+42 the answer should be 68+68+42 = 178. Similarly since 1+35+35 is bigger than 1+1+35, the answer of the second test case should be 1+35+35 = 71.

a,b中大数*2+小数即可

#include
#include
#include
#include
using namespace std;
int main()
{
	int T;
	scanf("%d",&T);
	while(T>0)
	{
		T--;
		int x,y;
		scanf("%d%d",&x,&y);
		if(x>y)
			printf("%d\n",x+x+y);
		else
			printf("%d\n",x+y+y);
	}
	return 0;
}