zoj_3710Friends

Friends

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Time Limit:2 Seconds Memory Limit:65536 KB

---

Alice lives in the country where people like to make friends. The friendship is bidirectional and if any two person have no less thankfriends in common, they will become friends in several days. Currently, there are totallynpeople in the country, andmfriendship among them. Assume that any new friendship is made only when they have sufficient friends in common mentioned above, you are to tell how many new friendship are made after a sufficiently long time.

Input

There are multiple test cases.

The first lien of the input contains an integerT(about 100) indicating the number of test cases. ThenTcases follow. For each case, the first line contains three integersn, m, k(1 ≤n≤ 100, 0 ≤m≤n×(n-1)/2, 0 ≤k≤n, there will be no duplicated friendship) followed bymlines showing the current friendship. Theithfriendship contains two integersu_i, v_i(0 ≤u_i, v_ii≠ v_i) indicating there is friendship between personu_iandv_i.

Note: The edges in test data are generated randomly.

Output

For each case, print one line containing the answer.

Sample Input

3
4 4 2
0 1
0 2
1 3
2 3
5 5 2
0 1
1 2
2 3
3 4
4 0
5 6 2
0 1
1 2
2 3
3 4
4 0
2 0

Sample Output

2
0
4

STL set + map

#include
#include
#include
#include

昨天训练赛这样写就WA，想不明白

for (it = Map[i].begin(); it != Map[i].end(); it++)
{
	if(Map[j].find(*it) != Map[j].end())
	{
		num++;
		if(num >= k)
		{
			ans++;
			flag = true;
			Map[i].insert(j);
			Map[j].insert(i);
			break;
		}
	}
}