mysql的sql语句根据经纬度查询距离排序

SELECT
    id,
s_subbran_name,
    n_longitude,
    n_latitude,


    ROUND(
        6378.138 * 2 * ASIN(
            SQRT(
                POW(
                    SIN( ( 40.042307 * PI() / 180 - n_latitude * PI() / 180 ) / 2
                    ),
                    2
                ) + COS(40.042307 * PI() / 180) * COS(n_latitude * PI() / 180) * POW(
                    SIN(
                        (
                            116.317205 * PI() / 180 -   n_longitude * PI() / 180
                        ) / 2
                    ),
                    2
                )
            )
        ) * 1000
    ) AS juli
FROM
subbranch_info
ORDER BY
    juli DESC