LeetCode[Hard]------843. Guess the Word

问题描述

This problem is an interactive problem new to the LeetCode platform.

We are given a word list of unique words, each word is 6 letters long, and one word in this list is chosen as secret.

You may call master.guess(word) to guess a word. The guessed word should have type string and must be from the original list with 6 lowercase letters.

This function returns an integer type, representing the number of exact matches (value and position) of your guess to the secret word. Also, if your guess is not in the given wordlist, it will return -1 instead.

For each test case, you have 10 guesses to guess the word. At the end of any number of calls, if you have made 10 or less calls to master.guess and at least one of these guesses was the secret, you pass the testcase.

Besides the example test case below, there will be 5 additional test cases, each with 100 words in the word list. The letters of each word in those testcases were chosen independently at random from ‘a’ to ‘z’, such that every word in the given word lists is unique.

Example 1:

Input: secret = “acckzz”, wordlist = [“acckzz”,“ccbazz”,“eiowzz”,“abcczz”]
Explanation:
master.guess(“aaaaaa”) returns -1, because “aaaaaa” is not in wordlist.
master.guess(“acckzz”) returns 6, because “acckzz” is secret and has all 6 matches.
master.guess(“ccbazz”) returns 3, because “ccbazz” has 3 matches.
master.guess(“eiowzz”) returns 2, because “eiowzz” has 2 matches.
master.guess(“abcczz”) returns 4, because “abcczz” has 4 matches.

We made 5 calls to master.guess and one of them was the secret, so we pass the test case.

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简单翻译一下，这是一道LeetCode上的一种新型的交互类题目。有一个wordlist，里面有许多由6个character组成的字符串。从wordlist里面随便选一个字符串作为secret，现在让你用10次机会去猜出这个secret到底是wordlist里面的哪个。

思路：

思路：这是一道新类型的题，要在10回合内找wordlist中隐藏的那个secret单词。此题没有限制结果，所以10回合后可能找到，也可能找不到。首先我们随机在wordlist里面选一个String次来guess，看有多少字符匹配。然后遍历wordlist，把字符匹配个数与String 相等的字符串全部取出，更新wordlist。此时就可以排除许多错误的string，最后的secret也一定在更新后的wordlist中。wordlist的size逐渐减小，我们的工作量也逐渐减小。当master.guess等于6或者满足10个回合后，代码结束。

代码：

public void findSecretWord(String[] wordlist, Master master) {
		for (int i = 0, match = 0; i < 10 && match < 6; ++i) {
			String guess = wordlist[new Random().nextInt(wordlist.length)];
			match = master.guess(guess);
			List<String> wordlist2 = new ArrayList<>();
			for (String word : wordlist)
				if (match(guess, word) == match)
					wordlist2.add(word);
			wordlist = wordlist2.toArray(new String[wordlist2.size()]);
		}
	}

	private int match(String a, String b) {
		int matches = 0;
		for (int i = 0; i < a.length(); ++i)
			if (a.charAt(i) == b.charAt(i))
				matches++;
		return matches;
	}

仅用于个人的学习理解，如需转载，请标明出处：
https://blog.csdn.net/sc19951007/article/details/83713197