Java : List中 根据map的某个key去重

  话不多说,看代码和效果

 

     /**
     * 根据map中的某个key 去除List中重复的map
     * @author  shijing
     * @param list
     * @param mapKey
     * @return
     */
    public static List> removeRepeatMapByKey(List> 
           list, String mapKey){
        if (CollectionUtils.isNullOrEmpty(list)) return null;

        //把list中的数据转换成msp,去掉同一id值多余数据,保留查找到第一个id值对应的数据
        List> listMap = new ArrayList<>();
        Map msp = new HashMap<>();
        for(int i = list.size()-1 ; i>=0; i--){
            Map map = list.get(i);
            String id = (String)map.get(mapKey);
            map.remove(mapKey);
            msp.put(id, map);
        }
        //把msp再转换成list,就会得到根据某一字段去掉重复的数据的List
        Set mspKey = msp.keySet();
        for(String key: mspKey){
            Map newMap = msp.get(key);
            newMap.put(mapKey, key);
            listMap.add(newMap);
        }
        return listMap;
    }

测试:

public static void main(String[] args) {
        Map msp = new HashMap();
        List> list = new ArrayList>();
        List> listMap = new ArrayList>();
        Map map1 = new HashMap();
        map1.put("id", "1123");
        map1.put("name", "张三");
        Map map2 = new HashMap();
        map2.put("id", "2");
        map2.put("name", "李四");
        Map map3 = new HashMap();
        map3.put("id", "1123");
        map3.put("name", "王五");
        Map map4 = new HashMap();
        map4.put("id", "3");
        map4.put("name", "赵六");
        list.add(map1);
        list.add(map2);
        list.add(map3);
        list.add(map4);
        System.out.println("初始数据:" + list.toString());
        System.out.println("去重之后:" + removeRepeatMapByKey(list,"id"));
    }

结果:

初始数据:[{name=张三, id=1123}, {name=李四, id=2}, {name=王五, id=1123}, {name=赵六, id=3}]
去重之后:[{name=李四, id=2}, {name=赵六, id=3}, {name=张三, id=1123}]

 

 

 

你可能感兴趣的:(个人心得,代码工具类,java代码工具类)