1108 Finding Average (20 分)

The basic task is simple: given N real numbers, you are supposed to calculate their average. But what makes it complicated is that some of the input numbers might not be legal. A legal input is a real number in [−1000,1000] and is accurate up to no more than 2 decimal places. When you calculate the average, those illegal numbers must not be counted in.

Input Specification:

Each input file contains one test case. For each case, the first line gives a positive integer N (≤100). Then N numbers are given in the next line, separated by one space.

Output Specification:

For each illegal input number, print in a line ERROR: X is not a legal number where X is the input. Then finally print in a line the result: The average of K numbers is Y where K is the number of legal inputs and Y is their average, accurate to 2 decimal places. In case the average cannot be calculated, output Undefined instead of Y. In case K is only 1, output The average of 1 number is Y instead.

Sample Input 1:

7
5 -3.2 aaa 9999 2.3.4 7.123 2.35

Sample Output 1:

ERROR: aaa is not a legal number
ERROR: 9999 is not a legal number
ERROR: 2.3.4 is not a legal number
ERROR: 7.123 is not a legal number
The average of 3 numbers is 1.38

Sample Input 2:

2
aaa -9999

Sample Output 2:

ERROR: aaa is not a legal number
ERROR: -9999 is not a legal number
The average of 0 numbers is Undefined

使用:sscanf()和sprintf() 一个用于格式化从字符串中读入变量,一个用于格式化从变量输出到字符串中,若二个字符串比较不相等,等说明不合法。

#include
#include
#include
#include
#include
#include
#include
#include
#include
#include
#include
using namespace std;
#define ll long long
#define vi vector
#define pii pair
#define x first
#define y second
const int maxn=110;
int n,cnt=0;
int main()
{
    cin>>n;
    double temp,res=0;
    char a[maxn],b[maxn];
    for(int i=0;i1000)
        {
            printf("ERROR: %s is not a legal number\n",a);
            continue;
        }
        else
        {
            res+=temp;
            cnt++;
        }
    }
    if(cnt==1)
      printf("The average of 1 number is %0.2f\n",res);
    else if(cnt>1)
      printf("The average of %d numbers is %0.2f\n",cnt,res/cnt);
    else
      printf("The average of 0 numbers is Undefined");
    return 0;
}

 

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