import re
import functools
def minus_operator_handler(formula): # 减运算符处理程序
# '''处理一些特殊的减号运算'''
minus_operators = re.split("-", formula)
calc_list = re.findall("[0-9]", formula)
if minus_operators[0] == '': # 第一值肯定是负号
calc_list[0] = '-%s' % calc_list[0]
res = functools.reduce(lambda x, y: float(x) - float(y), calc_list)
print("\033[33;1m减号[%s]处理结果:\033[0m" % formula, res)
return res
def remove_duplicates(formula): # 删除重复项
formula = formula.replace("++","+")
formula = formula.replace("+-","-")
formula = formula.replace("-+","-")
formula = formula.replace("--","+")
formula = formula.replace("- -","+")
return formula
def compute_mutiply_and_dividend(formula): # 计算乘法和除法
# '''算乘除,传进来的是字符串噢'''
operators = re.findall("[*/]", formula )
calc_list = re.split("[*/]", formula )
res = None
for index,i in enumerate(calc_list):
if res:
if operators[index-1] == "*":
res *= float(i)
elif operators[index-1] == "/":
res /= float(i)
else:
res = float(i)
print("\033[31;1m[%s]运算结果=\033[0m" % formula, res)
return res
def handle_minus_in_list(operator_list, calc_list):
'''有的时候把算术符和值分开后,会出现这种情况 ['-', '-', '-'] [' ', '14969037.996825399 ', ' ', '12.0/ 10.0 ']
这需要把第2个列表中的空格都变成负号并与其后面的值拼起来,恶心死了
'''
for index, i in enumerate(calc_list):
if i == '': # 它其实是代表负号,改成负号
calc_list[index + 1] = i + calc_list[index + 1].strip()
def handle_special_occactions(plus_and_minus_operators, multiply_and_dividend):
'''有时会出现这种情况 , ['-', '-'] ['1 ', ' 2 * ', '14969036.7968254'],2*...后面这段实际是 2*-14969036.7968254,需要特别处理下,太恶心了'''
for index, i in enumerate(multiply_and_dividend):
i = i.strip()
if i.endswith("*") or i.endswith("/"):
multiply_and_dividend[index] = multiply_and_dividend[index] + plus_and_minus_operators[index] + \
multiply_and_dividend[index + 1]
del multiply_and_dividend[index + 1]
del plus_and_minus_operators[index]
return plus_and_minus_operators, multiply_and_dividend
def compute(formula):
'''这里计算是的不带括号的公式'''
formula = formula.strip("()") # 去除外面包的拓号
formula = remove_duplicates(formula) # 去除外重复的+-号
plus_and_minus_operators = re.findall("[+-]", formula)
multiply_and_dividend = re.split("[+-]", formula) # 取出乘除公式
if len(multiply_and_dividend[0].strip()) == 0: # 代表这肯定是个减号
multiply_and_dividend[1] = plus_and_minus_operators[0] + multiply_and_dividend[1]
del multiply_and_dividend[0]
del plus_and_minus_operators[0]
plus_and_minus_operators, multiply_and_dividend = handle_special_occactions(plus_and_minus_operators,
multiply_and_dividend)
for index, i in enumerate(multiply_and_dividend):
if re.search("[*/]", i):
sub_res = compute_mutiply_and_dividend(i)
multiply_and_dividend[index] = sub_res
# 开始运算+,-
print(multiply_and_dividend, plus_and_minus_operators)
total_res = None
for index, item in enumerate(multiply_and_dividend):
if total_res: # 代表不是第一次循环
if plus_and_minus_operators[index - 1] == '+':
total_res += float(item)
elif plus_and_minus_operators[index - 1] == '-':
total_res -= float(item)
else:
total_res = float(item)
print("\033[32;1m[%s]运算结果:\033[0m" % formula, total_res)
return total_res
def calc(formula):
'''计算程序主入口, 主要逻辑是先计算拓号里的值,算出来后再算乘除,再算加减'''
parenthesise_flag = True
calc_res = None # 初始化运算结果为None,还没开始运算呢,当然为None啦
while parenthesise_flag:
m = re.search("\([^()]*\)", formula) # 找到最里层的拓号
if m:
# print("先算拓号里的值:",m.group())
sub_res = compute(m.group())
formula = formula.replace(m.group(), str(sub_res))
else:
print('\033[41;1m----没拓号了...---\033[0m')
print('\n\n\033[42;1m最终结果:\033[0m', compute(formula))
parenthesise_flag = False # 代表公式里的拓号已经都被剥除啦
if __name__ == '__main__':
# res = calc("1 - 2 * ( (60-30 +(-40/5) * (9-2*5/3 + 7 /3*99/4*2998 +10 * 568/14 )) - (-4*3)/ (16-3*2) )")
res = calc(
"1 - 2 * ( (60-30 +(-9-2-5-2*3-5/3-40*4/2-3/5+6*3) * (-9-2-5-2*5/3 + 7 /3*99/4*2998 +10 * 568/14 )) - (-4*3)/ (16-3*2) )")
