[BZOJ1316]树上的询问（点分治+二分）

题目描述

传送门

题解

点分治裸题
每一次求出deep之后排序然后两次二分
因为点分常数很大做一次求m个比做m次快得多

代码

#include
#include
#include
#include
#include
using namespace std;
#define N 10005

int n,x,y,z,m,sum,root;
int q[N],ans[N];
int tot,point[N],nxt[N*2],v[N*2],c[N*2];
int size[N],big[N],d[N],deep[N];
bool vis[N];

void add(int x,int y,int z)
{
    ++tot; nxt[tot]=point[x]; point[x]=tot; v[tot]=y; c[tot]=z;
}
void getroot(int x,int fa)
{
    size[x]=1;big[x]=0;
    for (int i=point[x];i;i=nxt[i])
        if (v[i]!=fa&&!vis[v[i]])
        {
            getroot(v[i],x);
            size[x]+=size[v[i]];
            big[x]=max(big[x],size[v[i]]);
        }
    big[x]=max(big[x],sum-size[x]);
    if (big[x]x;
}
void getdeep(int x,int fa)
{
    deep[++deep[0]]=d[x];
    for (int i=point[x];i;i=nxt[i])
        if (v[i]!=fa&&!vis[v[i]])
        {
            d[v[i]]=d[x]+c[i];
            getdeep(v[i],x);
        }
}
int findl(int l,int r,int k)
{
    int ans=0;
    while (l<=r)
    {
        int mid=(l+r)>>1;
        if (deep[mid]==k) ans=mid,r=mid-1;
        else if (deep[mid]1;
        else r=mid-1;
    }
    return ans;
}
int findr(int l,int r,int k)
{
    int ans=-1;
    while (l<=r)
    {
        int mid=(l+r)>>1;
        if (deep[mid]==k) ans=mid,l=mid+1;
        else if (deep[mid]1;
        else r=mid-1;
    }
    return ans;
}
int calc(int x,int now,int k)
{
    d[x]=now;deep[0]=0;
    getdeep(x,0);
    sort(deep+1,deep+deep[0]+1);
    int t=0;
    for (int i=1;i<=deep[0];++i)
    {
        if (deep[i]+deep[i]>k) break;
        int l=findl(i,deep[0],k-deep[i]);
        int r=findr(i,deep[0],k-deep[i]);
        t+=r-l+1;
    }
    return t;
}
void dfs(int x)
{
    for (int i=1;i<=m;++i)
        ans[i]+=calc(x,0,q[i]);
    vis[x]=1;
    for (int i=point[x];i;i=nxt[i])
        if (!vis[v[i]])
        {
            for (int j=1;j<=m;++j)
                ans[j]-=calc(v[i],c[i],q[j]);
            sum=size[v[i]];root=0;
            getroot(v[i],0);
            dfs(root);
        }
}

int main()
{
    scanf("%d%d",&n,&m);
    for (int i=1;i"%d%d%d",&x,&y,&z);
        add(x,y,z),add(y,x,z);
    }
    for (int i=1;i<=m;++i) scanf("%d",&q[i]);
    big[0]=N;
    sum=n;root=0;
    getroot(1,0);
    dfs(root);
    for (int i=1;i<=m;++i)
        if (ans[i]) puts("Yes");
        else puts("No");
}