解析atlas文件

有些引擎比如libgdx打包图片资源时，是atlas。

想获取资源就要解析了。把这个文件放到要解析的资源文件夹下面编译输入要解析的文件名就可以了。

# -*- coding: utf-8 -*-

import os
import sys
import os.path
import shutil
import Image

fileName = raw_input('输入要解析的文件名:')

if fileName.find('.png') != -1:
    fileName = fileName[:-4]

pngName = fileName + '.png'
atlasName = fileName + '.atlas'

print pngName,atlasName

big_image = Image.open(pngName)
atlas = file(atlasName, "r");


curPath = os.getcwd()# 当前路径
aim_path = os.path.join(curPath, fileName)
print aim_path
if os.path.isdir(aim_path):
    shutil.rmtree(aim_path,True)#如果有该目录,删除
os.makedirs(aim_path)

#
_line = atlas.readline();
_line = atlas.readline();
_line = atlas.readline();
_line = atlas.readline();

while True:
    line1 = atlas.readline() # name
    if len(line1) == 0:
        break
    else:
        line2 = atlas.readline() # rotate
        line3 = atlas.readline() # xy
        line4 = atlas.readline() # size
        line5 = atlas.readline() # orig
        line6 = atlas.readline() # offset
        line7 = atlas.readline() # index
        
        name = line1.replace("\n","") + ".png";
        
        args = line4.split(":")[1].split(",");
        width = int(args[0])
        height= int(args[1])
            
        args = line3.split(":")[1].split(",");
        ltx = int(args[0])
        lty = int(args[1])
            
        rbx = ltx+width
        rby = lty+height
        
        print name,width,height,ltx,lty,rbx,rby

        result_image = Image.new("RGBA", (width,height), (0,0,0,0))
        rect_on_big = big_image.crop((ltx,lty,rbx,rby))
        print(rect_on_big)
        result_image.paste(rect_on_big, (0,0,width,height))
        result_image.save(aim_path+'/'+name)
atlas.close()
del big_image