1.用穷举法输入1-100的素数
#include
#include
using namespace std;
bool isprime(int n)
{
if (n <= 1)
return false;
for (int i = 2; i <= sqrt(n); i++)
if (n%i == 0)
return false;
return true;
}
int main()
{
int cnt = 0;
for(int i=1;i<=100;i++)
if (isprime(i))
{
cout << i << " ";
cnt++;
if (cnt % 5 == 0)
cout << endl;
}
return 0;
}
#include
#include
using namespace std;
int fun(int n)
{
if (n == 1)
return 1;
else
return fun(n - 1) + n;
}
int main()
{
int n;
cin >> n;
cout << fun(n) << endl;
return 0;
}
3.请完成函数 int index(char *s,char *t) 函数的作用是返回字符串t出现在字符串第一次最左边得下标 若不是s得字串 则返回-1.
#include
#include
using namespace std;
int index(char *s, char *t)
{
char *p = s ,* q = t;
int a = strlen(p);
int b = strlen(q);
for(int i = 0; i < a; i++) {
int j;
for (j = 0; j < b; j++)
{
if (p[i + j] != q[j])
break;
}
if (j == b)
return i;
}
return -1;
}
int main()
{
char a[100], b[100];
cin >> a >> b;
cout << index(a, b) << endl;
return 0;
}
4.请编写 抽象类shape,然后派生出Rectangle和Circle类 要求完成计算机面积
// ConsoleApplication10.cpp : 此文件包含 "main" 函数。程序执行将在此处开始并结束。
//
#include
#include
using namespace std;
class Shape {
public:
virtual void Aear() = 0;
virtual void input() = 0;
};
class Rectangle :public Shape {
private:
double width;
double lenth;
public:
void input()
{
cout << "输入长方形的长和宽:" << endl;
cin >> width >> lenth;
}
void Aear()
{
cout << "长方形的面积:" << width * lenth << endl;
}
};
class Circle :public Shape{
private:
double r;
public:
void input()
{
cout << "输入圆形的半径:" << endl;
cin >> r;
}
void Aear()
{
cout << "圆形的面积:" << 3.14*r*r << endl;
}
};
int main()
{
Shape *s = new Rectangle();
s->input();
s->Aear();
s = new Circle();
s->input();
s->Aear();
return 0;
}
5 每次从键盘读取一行文本,输出到文件“a.txt”中,当用户输入空行是结束
#include
#include
#include
using namespace std;
int main()
{
ofstream outfile("a.txt", ios::out);
if (!outfile)
{
cerr << "打开文件错误!" << endl;
exit(1);
}
char s[100];
cin.getline(s, 100);
for(int i =0; i < strlen(s); i++)
{
outfile.write((char*)&s[i], 1);
}
outfile.close();
return 0;
}