【leetcode】反转整数（Reverse Integer）【python】

class Solution:
    def reverse(self, x):
        """
        :type x: int
        :rtype: int
        """
        if x == -2 ** 31:
            return 0
        reversestr = ''
        if x < 0:
            reversestr = '-'
        x = abs(x)
        string = str(x)
        for i in range(len(string) - 1, -1, -1):
            if i == len(string) - 1 and string[i] == 0:
                continue
            reversestr += string[i]
        x = int(reversestr)
        if x < -2 ** 31 or x > 2 ** 31 - 1:
            return 0
        else:
            return x
x = 1534236469
sol = Solution()
print(sol.reverse(x))