Can not perform this action after onSaveInstanceState

异常日志

Caused by: java.lang.IllegalStateException: Can not perform this action after onSaveInstanceState
    at android.support.v4.app.FragmentManagerImpl.checkStateLoss(FragmentManager.java:1533)
    at android.support.v4.app.FragmentManagerImpl.popBackStackImmediate(FragmentManager.java:603)
    at android.support.v4.app.FragmentActivity.onBackPressed(FragmentActivity.java:179)
    at com.shirley.tealeaf.base.BaseActivity.onBackPressed(BaseActivity.java:129)
    at com.shirley.tealeaf.login.LoginActivity.isCompletionSuccess(LoginActivity.java:159)
    at com.shirley.tealeaf.presenter.LoginPresenter$3.call(LoginPresenter.java:86)
    at com.shirley.tealeaf.presenter.LoginPresenter$3.call(LoginPresenter.java:83)
    at rx.internal.util.ActionSubscriber.onNext(ActionSubscriber.java:39)
    at rx.observers.SafeSubscriber.onNext(SafeSubscriber.java:134)
    at rx.internal.operators.OnSubscribeOnAssembly$OnAssemblySubscriber.onNext(OnSubscribeOnAssembly.java:124)
    at rx.internal.operators.OperatorObserveOn$ObserveOnSubscriber.call(OperatorObserveOn.java:224)
    at rx.android.schedulers.LooperScheduler$ScheduledAction.run(LooperScheduler.java:107)

异常说明

Fragment在API < 11之前完美运行，在 API > 11之后则会出现此bug

解决方案

重写onSaveInstanceState方法

不要在onSaveInstanceState方法中调用super.方法

@Override
protected void onSaveInstanceState(Bundle outState) {
    //No call for super(). Bug on API Level > 11.
}

保存实例

这是一个support包中比较常见的bug，如果你想保存一些实例，你可以：

@Override
protected void onSaveInstanceState(Bundle outState) {
    outState.putString("WORKAROUND_FOR_BUG_19917_KEY", "WORKAROUND_FOR_BUG_19917_VALUE");
    super.onSaveInstanceState(outState);
}

出现场景

如果你的activity在后台被系统杀死后，你执行了fragment的提交事务操作，则会出现此bug。为了避免发生该bug，你应该使用commitAllowingStateLoss()

参考Fragment Transactions & Activity State Loss

注意

• 在Honeycomb之前，不要在onPause()方法中commit() 事务；在Honeycomb之后，不要在onStop()方法中commit() 事务
• 在Activity生命周期方法中提交事务时要小心。尽量在onCreate()，onResumeFragments()和onPostResume()方法中提交
• 使用commitAllowingStateLoss()作最后的手段