拼接查询条件为list集合的sql函数

当deptId 为1时 sql语句不做更改
当deptId 为其他数字时 list中的id项作为sql查询条件

刚开始编写的时候思路是用or语句进行循环遍历 重复加上or的sql语句来查询
发现比较复杂 最后采取了sql的in函数来实现

public String getDeptIdSql(List deptIdList){
    Iterator it = deptIdList.iterator();
    //当部门id为1时  不采用筛选
    while(it.hasNext()){
          Long deptId = it.next();
          if(deptId == 1){
                return "";
          }
    }
          //拼接in条件语句
          String s = "";
          for(int i = 0; i < deptIdList.size();i++){
                if(i!=(deptIdList.size()-1)){
                      s += deptIdList.get(i) + ",";
                }else{
                      s += deptIdList.get(i);
                }
          }
          String sql = " and mtMaintenanceStandard.dept_Id in (" + s + ") ";
          return sql;
}

编写完成后发现函数有可以提高函数的复用性，将mtMaintenanceStandard.dept_Id设为传入的变量
最后得到

public String getDeptIdSql(String condition,List deptIdList){
    Iterator it = deptIdList.iterator();
    //当部门id为1时  不采用筛选
    while(it.hasNext()){
          Long deptId = it.next();
          if(deptId == 1){
                return "";
          }
    }
          //拼接in条件语句
          String s = "";
          for(int i = 0; i < deptIdList.size();i++){
                if(i!=(deptIdList.size()-1)){
                      s += deptIdList.get(i) + ",";
                }else{
                      s += deptIdList.get(i);
                }
          }
          String sql = " and " + condition + " in (" + s + ") ";
          return sql;
}

更为通用的版本是不用判断deptId是否为1

public String getDeptIdSql(String condition,List deptIdList){
          String s = "";
          for(int i = 0; i < deptIdList.size();i++){
                if(i!=(deptIdList.size()-1)){
                      s += deptIdList.get(i) + ",";
                }else{
                      s += deptIdList.get(i);
                }
          }
          String sql = " and " + condition + " in (" + s + ") ";
          return sql;
}