[PAT A1054]The Dominant Color

[PAT A1054]The Dominant Color

题目描述

Behind the scenes in the computer's memory, color is always talked about as a series of 24 bits of information for each pixel. In an image, the color with the largest proportional area is called the dominant color. A strictly dominant color takes more than half of the total area. Now given an image of resolution M by N (for example, 800×600), you are supposed to point out the strictly dominant color.

输入格式

Each input file contains one test case. For each case, the first line contains 2 positive numbers: M (≤800) and N (≤600) which are the resolutions of the image. Then N lines follow, each contains M digital colors in the range [0,2^{24}​​). It is guaranteed that the strictly dominant color exists for each input image. All the numbers in a line are separated by a space.

输出格式

For each test case, simply print the dominant color in a line.

输入样例

5 3

0 0 255 16777215 24

24 24 0 0 24

24 0 24 24 24

输出样例

24

解析

题目很简单,意思就是给出N*M的矩阵,要求N*M个数中超过半数的那个数,由于保证一定有解,我们甚至可以不需要判断是否存在这样的数。

#include
#include
using namespace std;
mapcolors;
int main()
{
	int m, n;
	scanf("%d%d", &m, &n);
	for (int i = 0; i < n; i++) {
		for (int j = 0; j < m; j++) {
			int temp;
			scanf("%d", &temp);
			colors[temp]++;
		}
	}
	int count = m * n;
	for (map::iterator it = colors.begin(); it != colors.end(); it++) {
		if (it->second > m*n / 2) printf("%d",it->first);
	}
	return 0;
}

 

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