JavaWeb --Servlet编写一个动态网页

1.在javaee环境下 新建dynamic web project 注意选择生成web.xml文件。此文件用来配置web页面属性

2.在web.xml配置文件里 配置映射关系

 
      FirstServlet             //servlet名
      yangyang.FirstServlet //包名.类名
   
  
      FirstServlet
      /hello  //建立虚拟映射
  

3.重写doget和dopost方法：

protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
		System.out.println("get");
		response.setContentType("text/html;charset=utf-8");  //为了防止乱码 设置编码方式
		PrintWriter out=response.getWriter();  //获取读写流
		out.println("");   //把html文件里的内容打印
		out.println("");
		out.println("");
		out.println("");
		out.println("");//有特殊符号的地方加转义字符\
		out.println("");
		out.println("");
		out.println("
这是一个动态网页界面!
");
		out.println("");
		out.println("");
	}

	/**
	 * @see HttpServlet#doPost(HttpServletRequest request, HttpServletResponse response)
	 */
	protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
		System.out.println("post");   
	}

4.运行tomcat

5.在网页里输入http://localhost:8080/webpoject1/hello 

网页显示效果如下