Java Web 入门学习4：响应Response

Java Web 入门学习3：请求Request已经成功发送了get和post请求，本文介绍获取页面响应。

修改servlet

打开Testservlet.java，在doGet中添加代码

	response.setContentType("text/html;charset=utf-8");
	PrintWriter message = response.getWriter();
	message.write("欢迎您，"+username);

添加完成后代码如下

protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
	System.out.println("This is doGet");
	String username=request.getParameter("username1");
	String password=request.getParameter("password1");
	System.out.println("用户："+username+"，密码："+password+"，登录！");
		
	response.setContentType("text/html;charset=utf-8");//修改编码格式，避免中文乱码
	PrintWriter message = response.getWriter();
	message.write("欢迎您，"+username);
}

同样修改doPost方法，修改完成后

protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
	System.out.println("This is doPost");
	String username=request.getParameter("username2");
	String password=request.getParameter("password2");
	System.out.println("用户："+username+"，密码："+password+"，登录！");
		
	response.setContentType("text/html;charset=utf-8");
	PrintWriter message = response.getWriter();
	message.write("欢迎您，"+username);
}

测试

启动tomcat服务器，浏览器打开http://localhost:8080/mytestwebproject/Login.html

点击第一行的登录，get请求，获得响应信息

点击第二行的登录，post请求，获得响应信息