大哭！！!栽到了std::move手里！

项目里有这样的一个逻辑。
vectorvoid()>> _fs;
在其他线程里有fs.push_back(args); 
auto fs = std::move(_fs);
没错，_fs老是会无缘无故的清空，我一直以为是调度器的问题，
调试了一个下午加一个早上，结果知道有人提醒是move的问题，
原来一直以为move是返回个引用，可没想到返回的是右值引用，
调用的是移动拷贝构造。这是Cppreference里的。
#include 
#include 
#include 
#include 

int main()
{
    std::string str = "Hello";
    std::vector<std::string> v;

    // uses the push_back(const T&) overload, which means 
    // we'll incur the cost of copying str
    v.push_back(str);
    std::cout << "After copy, str is \"" << str << "\"\n";

    // uses the rvalue reference push_back(T&&) overload, 
    // which means no strings will be copied; instead, the contents
    // of str will be moved into the vector.  This is less
    // expensive, but also means str might now be empty.
    v.push_back(std::move(str));
    std::cout << "After move, str is \"" << str << "\"\n";

    std::cout << "The contents of the vector are \"" << v[0]
                                         << "\", \"" << v[1] << "\"\n";
}


总之，还是自己对接口不熟悉吃了亏。另外，在这里吐槽一下csdn这编辑器真垃圾。