Python-CodeWars-17-11-26

CodeWars-1126

# -*- coding: utf-8 -*-
# @Time    : 2017/11/26 上午11:59
# @Author  : SkullFang
# @Email   : [email protected]
# @File    : 11-26.py
# @Software: PyCharm
import math
def remove_char(s):
    if len(s)>2 :
        return s[1:-1]
    else:
        return ''


    #your code here


"""
def remove_char(s):
    return '' if len(s) <= 2 else s[1:-1]
"""

def find_next_square(sq):

    num=int(math.sqrt(sq))
    if num**2 == sq:
        return (num+1)**2


    # Return the next square if sq is a square, -1 otherwise
    return -1

# print(find_next_square(121))
"""
best
def find_next_square(sq):
    root = sq ** 0.5
    if root.is_integer(): #判断是不是一个整数
        return (root + 1)**2
    return -1
"""


def divisors(integer):
    li=[i for i in range(2,integer) if integer%i==0]
    if li:
        return li

    return '{0} is prime'.format(integer)
    pass

# print(divisors(13))

"""
best is me
"""

def make_negative( number ):
    return number if number<=0 else 0-number

# print(make_negative(0))

"""
best is me
"""
def duplicate_count(text):
    text=text.lower();
    li=[]
    cn=0;
    for i in range(0,len(text)):
        subli=text[i+1:]
        if text[i] in subli:
            if text[i] not in li:
                li.append(text[i])
                cn+=1

    return cn
    # Your code goes here

# print(duplicate_count("aA11"))

"""
best
def duplicate_count(s):
  return len([c for c in set(s.lower()) if s.lower().count(c)>1])
"""


def high_and_low(numbers):
    li=numbers.split(" ")
    re=[int(i) for i in li]

    max_number=max(re)
    min_number=min(re)
    numbers=str(max_number)+" "+str(min_number)


    return numbers

# print(high_and_low("4 5 29 54 4 0 -214 542 -64 1 -3 6 -6"))

"""
"""
def unique_in_order(iterable):
    li=list(iterable)
    re=[]

    if li:
        re.append(li[0])
        for i in range(1,len(li)):
            if li[i]!=li[i-1]:
                re.append(li[i])
    return re
# print(unique_in_order('A'))

def reverse_seq(n):
    return list(reversed([i for i in range(1,n+1)]))
    pass

# print(reverse_seq(5))

def no_space(x):
    li=x.split(" ")
    re=[_ for _ in li if _ !='']
    # print(re)
    return ''.join(re)
    #your code here

print(no_space('8 j 8   mBliB8g  imjB8B8  jl  B'))

总结：
1、判断一个数是不是整数可以用 is_interger()方法。
2、把列表转换为字符串可以用 ‘’.join(list)
3、字符串的分割用string.split(” “)