生产者和消费者-高并发(面试题)

面试题：写一个固定容量同步容器，拥有put和get方法，以及getCount方法，
能够支持，2个生产者线程及10个消费者线程的阻塞调用（经常问！）

1. 使用synchronized、wait和notify/notifyall来实现

package interview_test;
/** 
* 使用wait和notify/notifyall来实现 
* /
import java.util.LinkedList;
import java.util.concurrent.TimeUnit;

public class MyContainer1 {
	final private LinkedList list = new LinkedList<>();
	final private int MAX = 10;
	private int count = 0;
	
	public synchronized void put(T t) {
		while (list.size() == MAX) {  //想想为什么用while而不是if   while会再次检查！
			try {
				this.wait(); //effective java一书中说wait 99.9%和 while一起使用,wait释放锁
			} catch (InterruptedException e) {
				e.printStackTrace();
			}
		}
		list.add(t);
		++count;
		this.notifyAll(); //通知消费者线程进行消费
	}
	public synchronized T get() {
		T t = null;
		while (list.size() == 0) {
			try {
				this.wait();
			}catch (InterruptedException e) {
				e.printStackTrace();
			}
		}
		t = list.removeFirst(); //Removes and returns the first element from this list.
		count --;
		this.notifyAll();
		return t;
	}
	public static void main(String[] args) {
		MyContainer1 c = new MyContainer1<>();
		//启动消费者线程
		for (int i = 0; i < 10; i++) { //10个消费者线程
			new Thread(()->{
				for (int j = 0; j < 4; j++) {
					System.out.println(Thread.currentThread().getName()+"-->"+c.get());
				}
			}
		}
		System.out.println("等待2秒生产-开始");
		try {
			TimeUnit.SECONDS.sleep(2);
		} catch (InterruptedException e) {
			e.printStackTrace();
		}
		System.out.println("等待2秒生产-结束");
		//启动生产者线程
		for (int i = 0; i < 2; i++) { //2个生产者线程
			new Thread(()->{
				for (int j = 0; j < 8 ;j++) {
					c.put(Thread.currentThread().getName()+" "+j );
					System.out.println("生产者:"+Thread.currentThread().getName()+" "+j );
				}
			},"product"+i) .start();
		}		

原文链接：https://blog.csdn.net/it_qingfengzhuimeng/article/details/83796567